Question

7. Rust is iron (III) oxide (Fe2O3). The owner of a 1959 Cadillac convertible wants to

Answer 1

The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

What is a mole?

A mole is the mass of a substance that contains 6.023×10²³ particles of that substance.

To calculate the number of moles of iron (III) Oxide contained in 2.5 kg of the rust, we use the formula below.

Formula:

• n = R.m/m.m................. Equation 1

Where:

• n = number of mole of iron (III) oxide
• R.m = mass of iron (III) oxide that is involved in the reaction (rusting)
• m.m = molar mass of iron (III) oxide.

From the question,

Given:

• R.m = 2.5 kg = 2500 g

• m.m of Fe₂O₃ = [(2×56)+(3×16)] = (112+48) = 160 g/mol

Substitute these values into equation 1

• n = 2500/160
• n = 15.625 moles.

Hence, The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

Learn more about moles here: brainly.com/question/15356425