(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
First option: 
Step-by-step explanation:
<h3>
The complete exercise is: "The height of a hill, h(x), in a painting can be written as a function of x, the distance from the left side of the painting. Both h(x) and x are measured in inches 
. What is the height of the hill in the painting 3 inches from the left side of the picture?</h3>
You have the following function provided in the exercise:

You know that
represents the height of the hill (in inches) and "x" represents the distance from the left side of the painting (in inches)
Knowing that you can determine that, if the painting 3 inches from the left side of the picture, the value of "x" is the following:

Therefore, you need to find the value of
when
in order to solve this exercise.
So, the next step is to substitute
into the function:

And finally, you must evaluate in order to find
.
You get that this is:

Answer:
0, 1, 2, 3, 4 and 5
Step-by-step explanation:
In a nutshell, base six is a number system that employs the numbers 0 through 5 instead of 0 through 9 in each digit. As a result, a number that would be stated as 6 in base ten is written as 10. We count one, two, three, four, five, ten, eleven, twelve, thirteen, fourteen, fifteen, twenty, and so on.
Answer: 49/60
Step-by-step explanation:
(1/3+2/5)-1/4-(5/6-7/6)
Primero (5/6-7/6)
5/6-7/6=-2/6
1/3+2/5-1/4-(-2/6)
1/3+2/5-1/4+2/6
2/6=1/3
1/3+2/5-1/4+1/3
2/3+2/5-1/4
2/3=10/15
2/5=6/15
10/15+6/15-1/4
16/15-1/4
16/15=64/60
1/4=15/60
64/60-15/60=49/60
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3