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Hitman42 [59]
3 years ago
8

Choose the adverb and then decide which adjective it modifies in the sentence below.

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0
" especially "  is ur adverb...and it is modifying the adjective " good "
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Can you show examples of collinearpoints
Dominik [7]
Three or more points that lie on the same line are collinear points. for example let’s say points D , B and E like on line N. does this help?
6 0
3 years ago
Write the equation of the line passing through the points (2,-5) and (7,-3).
Grace [21]

Answer:

5y·2x=21

<em>\frac{y - y1}{y2 - y1}  =  \frac{x - x1}{x2 - x1}</em>

Step-by-step explanation:

using the formula above,you will find the equation 5y–2x=21

7 0
2 years ago
Percent of discount is 25% and the sale price is 40$ what is the original amount?
Crank
<span>Percent of discount is 25% and the sale price is 40$ what is the original amount? $160

percent of discount is 5% and the sale price is 57$ what is the original amount? $60

percent of discount is 80% and the sale price is 90$ what is the original amount? $112.5

percent of discount is 15% and the sale price is 146.54$ what is the original 
amount? $976.93

the original price is 60$ and the sale price is 45$ what is the percent of discount? 25%

original price is 82$ and the sale price is 65.60$ what is the percent of discount? 20%

original price is 95$ and the sale price is 61.75$ what is the percent of discount? 35%</span>
6 0
3 years ago
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
5/4- square root of 3
ss7ja [257]
5/4 - square root of 3 = -0.48 

8 0
3 years ago
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