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4 years ago

If you were given the equation: 3x-2=19, what would be the justification for the first step after “Given”?

Mathematics

2 answers:

crimeas [40]4 years ago

8 0

The answer to that is 7 but i dont get the last part

Montano1993 [528]4 years ago

4 0

Answer:

Addition

Step-by-step explanation:

3x=21

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One-variable Statistics:Question 4

dusya [7]

Answer:

2:The data distribution is symmetric.

Step-by-step explanation:

6 0

3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

3 years ago

anita has two sisters and three brothers. the mean of all their ages is 6 years. what will their mean age be 10 years from now?t

pogonyaev

Answer:
Now: 6 yr mean age
in 10 yrs? 16 yr mean age
in 20 yrs? 26 yr mean age

Why? Because regardless of the relationship between each sibling's age, your always adding the 10yrs to each individual, which you are then dividing out to determine the mean age. See proof below:

Including anita, there are 6 people. We'll define each age as an unknown variable. Assume we know nothing about the relationships between their ages

for example sake
anita's age = a
sister 1's age = b
sister 2's age = c
brother 1's age = d
brother 2's age = e
brother 3's age = f

Now:
mean age = (a + b + c + d + e + f)/(6 people) = 6 yrs

in 10 yrs:
mean age = ((a+10) + (b+10) + (c+10) + (d+10) + (e+10) + (f+10))/(6 people)
mean age = (a + b + c + d + e + f + 60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + (60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + 10

Notice the first term is the same expression of the mean age for "Now"
Thus, in 10 yrs:
mean age = 6 + 10 = 16 yrs

The same principle applies for "x" yrs from now, as long as we know what the mean age is "Now"

3 0

4 years ago

Read 2 more answers

6+x6+x 6+x 6, plus, x when x=3x=3 x=3 x, equals, 3 .

fgiga [73]

Answer:

$2196$

Step-by-step explanation:

Okay so we have $6+x^{6} +x^{6} +x^{6} +x$ when $x=3$ since we know that $x=3$ we can rewrite the problem as $6+3^{6}+3^{6}+3^{6}+3$ then it can be rewritten as $(6+3)+(3*3^{6})$ which would then become $(9)+(3*729)$ then $(9)+(2187)$ which finally equals $2196$ .

6 0

4 years ago

Is anyone else having problems looking for answers?

denpristay [2]

I am ;-;

Doing a quiz right now- T^T

5 0

3 years ago