The most appropriate answer is D ! temperature !
as when temperature increases KE increases and the collision factor and frequency increases !
Answer:
All three are present
Explanation:
Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble:
.
- Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
- Secondly, addition of liquid ammonia would form a precipitate with silver:
; Silver hydroxide at higher temperatures decomposes into black silver oxide:
. - Thirdly, we also know we have
in the mixture, since addition of potassium chromate produces a yellow precipitate:
. The latter precipitate is yellow.
Hello my friend, Ionic bond is created when one atom takes an electron from another to fill its valence shell. Hope it helps☺☺
S orbital can hold 2
P can hold 6
D can hold 10
F can hold 14
Agents that antagonize the effects of acetylcholine are called anticholinergic.
<span>Anticholinergic blocks this neurotransmitter acetylcholine within the nervous system, by deactivating nerve impulses as a result of the binding of this neurotransmitter so that it cannot reach its receptor in nerve cells.</span>