The bond dipole moment<span> uses the idea of </span>electric dipole moment<span> to measure the </span>polarity<span> of a chemical bond within a </span>molecule<span>. It occurs whenever there is a separation of positive and negative charges. In the diagram above, option B exhibited a bond dipole moment. I hope this helps.</span>
Answer : The value of 
for this reaction is 36.18 kJ
Explanation :
First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.
As per first law of thermodynamic,
where,
= internal energy of the system
q = heat added or rejected by the system
w = work done
As we are given that:
q = 38.65 kJ
w = -2.47 kJ (system work done on surrounding)
Now put all the given values in the above expression, we get:
Therefore, the value of for this reaction is 36.18 kJ
Answer:
The first element is always named first, using entire element name.
Second element is named using its root and adding the suffix -ide.
Prefixes are used to indicate the number of atoms of each element that are present in the compound.
Explanation:
<h3>
Answer:</h3>
78.75 K
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial pressure, P₁ = 500 torr
- Initial temperature,T₁ = 225 K
- Initial volume, V₁ = 3.3 L
- Final volume, V₂ = 2.75 L
- Final pressure, P₂ = 210 torr
We are required to calculate the new temperature, T₂
- To find the new temperature, T₂ we are going to use the combined gas law;
- According to the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
We can calculate the new temperature, T₂;
Rearranging the formula;
T₂ =(P₂V₂T₁) ÷ (P₁V₁)
= (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)
= 78.75 K
Therefore, the new volume of the sample is 78.75 K
