Does mass<span> alone provide no information about the amount or size of a measured quantity? No, we need combine </span>mass<span> and </span>volume<span> into "one equation" to </span>determine<span> "</span>density<span>" provides more ... </span>g/mL<span>. An </span>object has<span> a mass of </span>75 grams<span> and a volume of </span>25 cc<span>. ... A </span>certain object weighs 1.25 kg<span> and </span>has<span> a </span>density of<span> </span>5.00 g/<span>mL</span>
Answer:
See explanation
Explanation:
1 mole of a gas occupies 22.4 L
x moles occupies 16.8 L
x = 1 mole * 16.8 L/22.4 L
x = 0.75 moles
number of moles = mass/molar mass
mass = number of moles * molar mass
mass = 0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g
the coefficient of the scientific notation answer = 2.25
the exponent of the scientific notation answer = 1
significant figures are there in the answer = 6
the right most significant figure in the answer = 3
2.
number of moles = 12.5g/38g/mol = 0.3289 moles
1 mole occupies 22.4 L
0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole
= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L
the coefficient of the scientific notation answer =7.37
the exponent of the scientific notation answer = 0
significant figures are there in the answer = 6
the right most significant figure in the answer= 3
Answer 2, because when you add salt to something, it cools faster (ex. When you add salt to an ice chest so that it stays cold) and it takes longer to boil (ex. When you boil salt out of ocean water so that its safe to drink) therefore, the more NaCl in the solution, the more it will exibit these properties
Answer:
The standard cell potential of the reaction is 0.78 Volts.
Explanation:

Reduction at cathode :
Reduction potential of
to Cu=
Oxidation at anode:

Reduction potential of
to Fe=
To calculate the
of the reaction, we use the equation:

Putting values in above equation, we get:

The standard cell potential of the reaction is 0.78 Volts.
Answer is: a possible identity for the unknown compound is C₃H₈.
m(binary compound) = 10.0 g.
m(H₂O) = 16.3 g; mass of water.
M(O₂) = 32 g/mol; molar mass of oxygen.
M(binary compound) = 1.38 · 32 g/mol.
M(binary compound) = 44.16 g/mol.
n(binary compound) = 10 g ÷ 44.16 g/mol.
n(binary compound) = 0.225 mol; amount of substance.
n(H₂O) = 16.3 g ÷ 18 g/mol.
n(H₂O) = 0.9 mol; amount of water.
m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.
m(H₂O) : n(binary compound) = 4 : 1.
Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.
Second element in compound is carbon:
M(X) = 44.16 g/mol - 8 · 1.01 g/mol.
M(X) = 36.08 g/mol ÷ 3.
M(C) = 12.01 g/mol.