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Nadya [2.5K]
3 years ago
8

A beaker contains 20.0 ml of a 50.0 g/L solution. What will the new concentration be if you add 40.0 mL of water?

Chemistry
1 answer:
Ronch [10]3 years ago
8 0

Answer:

moles SO42- = 0.0500 L x 0.20 M=0.010

moles Ba2+ = 0.0500 L x 0.10 M = 0.0050

Ba2+ + SO42- = BaSO4 (s)

moles SO42- in excess = 0.010 - 0.0050=0.0050

total volume = 100 mL = 0.100 L

[SO42-]= 0.0050/0.100= 0.050 M

[Na2SO4] = 2 /2 = 1 M

moles Na2SO4 = 2 M x 0.500 L = 0.500

mass Na2SO4 = 0.500 x 142 g/mol=71.0 g

moles MgBr2 = 46 /184 =0.25

moles Br- = 0.25 x 2 = 0.50

[Br-]= 0.50 / 0.50 L = 1 M

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GREYUIT [131]

Answer:HNO3 + NaOH → H2O + NaNO3

Explanation:

8 0
3 years ago
How many moles of Na2SO4 can be made with 7.28 mol of H2SO4?
Slav-nsk [51]

Answer:

7.28 mol Na2SO4

Explanation:

Since it is already in moles, all we have to do is use a molar ratio

A molar ratio is the proportions of reactants and products using the balanced equation. When writing a mole ratio, the given information must cross out with the right thing.

7.28 mol H2SO4 * 1 mol Na2SO4/1 H2SO4 = 7.28 mol Na2SO4

*notice how the H2SO4 crosses out

5 0
3 years ago
What is the approximate energy of a photon having a frequency of 4 x 10^7 Hz? (h = 6.6 x 10^-34 J . s)
BigorU [14]

Answer:

2.64 ×10^{-26} J

Explanation:

I think you should mark it a physics question instead but anyway.

---------------------------------------------------------------------------

The Planck equation should be applied:

E = hv , while E is energy of proton; h is Planck constant; and v is frequency.

E = 6.6 × 10^{-34} × 4 × 10^{7}

  = 6.6 × 4 × 10^{-27}

  = 2.64 ×10^{-26} J

3 0
3 years ago
An oxide ion, O2–, has:
sergij07 [2.7K]

Answer:

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6 0
2 years ago
Read 2 more answers
What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4
Lorico [155]

Answer:

3.2 L

Explanation:

Given data:

Mass of oxygen = 3.760 g

Pressure of gas = 88.4 Kpa (88.4×1000 = 88400 Nm⁻²)

Temperature = 19°C (19+273.15 = 292.15 K)

R = 8.314 Nm K⁻¹ mol⁻¹

Volume occupied = ?

Solution:

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 3.760 g/ 32 g/mol

Number of moles = 0.12 mol

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant

T = temperature in kelvin

V = nRT/P

V = 0.12 mol ×  8.314 Nm K⁻¹ mol⁻¹ × 292.15 K /88400 Nm⁻²

V = 291.472 Nm /88400 Nm⁻²

V = 0.0032 m³

m³ to L:

V = 0.0032×1000 = 3.2 L

4 0
3 years ago
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