1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
almond37 [142]
3 years ago
14

A sample of gas occupies a volume of 598.9 mL and has a pressure of 675.6 torr. What will the pressure of the sample of gas be i

f the volume is decreased to 235 mL? Be sure to include units with your answer.
Chemistry
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

<h2>1721.77 torr</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question we have

P_2 =  \frac{598.9 \times 675.6}{235}  =  \frac{404616.84}{235}  \\  = 1721.773787...

We have the final answer as

<h3>1721.77 torr </h3>

Hope this helps you

You might be interested in
How did Henry Moseley revise Mendeleev's periodic table? (Please answer A.S.A.P.)
CaHeK987 [17]
<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
</span>
Hope this helps!
5 0
3 years ago
Read 2 more answers
An object has a weight of 5.10 Newtons (N) at sea level, where the acceleration due to gravity is 9.81 m/s2.
RUDIKE [14]
Well, you could get the mass as m=\frac{G_0}{g_0} ad then g_1=\frac{G_1}{m}, where G_0 is the sea level weight, g_0 the sea level accel., g_1 the accel. above while G_1 the weight above.
8 0
3 years ago
Read 2 more answers
What atomic component contributes to many of the trends of elements
aivan3 [116]

what??? i need more information

3 0
3 years ago
What is the molar mass of Na2CO3? 60.0 g/mol 106.0 g/mol 118.0 g/mol 141.0 g/mol
Dmitry [639]

Answer is: the molar mass od sodium carbonate (Na₂CO₃) is 106.0 g/mol.

M(Na₂CO₃) = 2 · Ar(Na) + Ar(C) + 3 · Ar(O).

M(Na₂CO₃) = 2 · 23 + 12 + 3 · 16 · g/mol.

M(Na₂CO₃) = 46 + 12 + 48 · g/mol.

M(Na₂CO₃) = 106 g/mol; molar mass of sodium carbonate.

Ar is relative atomic mass (the ratio of the average mass of atoms of a chemical element to one unified atomic mass unit) of an element.

8 0
3 years ago
Identify the oxidizing agent in the reaction: sn(s) + 2h+(aq) → sn2+(aq) + h2(g)
mylen [45]
In the reaction Sn(s) + 2H+(aq) → Sn2+ (aq) + H2(g)
from this reaction, we get that Sn loses from 0 to 2 electrons so it's oxidized So it is the reducing agent.
and H  gains from 0 to 1 electrons so, it's reduced so ∴ it is the oxidizing agent
6 0
3 years ago
Read 2 more answers
Other questions:
  • In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?
    5·1 answer
  • Date a rock using half life
    14·1 answer
  • This biome has the nutrient poor soil
    6·1 answer
  • Which statement best describes saturation?
    7·2 answers
  • Which can be classified as a trace fossil
    7·2 answers
  • What element is being oxidized in the following redox reaction? Pb 2+(aq) + NH4 +(aq) - Pb(s) + NO3 (aq)
    8·1 answer
  • Electrons help create bonds between elements as they lie on the outside of an<br> atom.
    9·1 answer
  • You need to prepare an acetate buffer of pH 5.47 from a 0.809 M acetic acid solution and a 2.20 M KOH solution. If you have 680
    8·1 answer
  • Please help!!! (im really bad at chemistry)
    8·1 answer
  • A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!