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3 years ago

Is the question a statistical question

Mathematics

1 answer:

sveta [45]3 years ago

3 0

it’s a statistical question

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38 centimeters=_or_meters

KATRIN_1 [288]

38 centimeters = 0.38 meters

6 0

3 years ago

Given the hyperbola y = 1/x, find the area under the curve between x = 5 and x = 33 to 3 sig. dig. namely: integral subscript 5

Shtirlitz [24]

Answer:

(b) ln(33/5)

Step-by-step explanation:

$\int\limits_{5}^{33} \frac{1}{x} \, dx = \ln(x) \Big|\limits_{5}^{33} = \ln(33) - \ln(5) \\\\= ln(33/5)$

Remember that in general

$\ln(a) - \ln(b) = \ln(a/b)$

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2 years ago

Solve the inequality r 4-2(r-14)>0

klasskru [66]

R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)

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3 years ago

A statement and portions of the flowchart proof are shown. Which reason should appear in box labeled 1?

larisa [96]

Answer:

Angle Addition Postulate

Step-by-step explanation:

Given:

$m\angle UVW=30^{\circ}\\ \\m\angle WVX=75^{\circ}$

Prove:

$m\angle UVX=105^{\circ}$

Proof:

1. $m\angle UVX=m\angle UVW+m\angle WVX$ - Angle Addition Postulate

2. $m\angle UVW=30^{\circ}$ - given

3. $m\angle WVX=75^{\circ}$ - given

4. $m\angle UVX=30^{\circ}+75^{\circ}$ - Substitution Property of Equality

5. $m\angle UVX=105^{\circ}$ - Simplify

4 0

3 years ago

Graph the line with slope of 5/3 and goes through the point (2,1).

sladkih [1.3K]

Answer:

so graph your first point. (x=2, y=1)

Step-by-step explanation:

Your 5/3 is your rise over run. So go up 5 from 2 you should be at 7 and over 3 from your 1 so your next point would be (x=7, y=4) now get a ruler and connect your two points. make sure to use a ruler to make your line straight.

3 0

3 years ago