A 1.200 liter solution contains 35.0 grams of potassium iodide (KI). What is the molarity of this
1 answer:
Answer:
M = 0.177
Explanation:
First, we have to find the molar mass of potassium iodine (KI).
K = 39.098
I = 126.904
Now, add these values together to get the molar mass of KI
39.098 + 126.904 = 166.0028
Now, it's time to do a grams to moles conversion.
35.0 g KI * =
= 0.212 mol KI
Now, we can find the molarity of this solution.
Molarity (M) =
M = = 0.177 M
The molarity (M) of this solution is 0.177.
You might be interested in
Here we have to draw the mechanism of the reduction reaction between benzaldehyde and sodium borodeuteride to form the corresponding alcohol.
The reducing agent sodium borodeuteride can reduce the aldehydes to its corresponding alcohol. The reaction mechanism is shown in the attached image.
The reaction mechanism can be explained as-
The sodium borodeuteride is highly ionic in nature thus it remains as Na⁺ and BD₄⁻ The deuterium atom of BD₄⁻ attack the carbonyl carbon atom and substitute one of its deuterium as shown in the figure.
One molecule of sodium borodeuteride can reduce four molecules of benzaldehyde. The polar solvent like alcohol donates the proton as shown in the mechanism.
The converted alcohol contains the deuterium atom at the -C center. Thus benzaldehyde is converted to deuteroted benzyl alcohol.
Answer:
1. ¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β
2. ³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β
3. ¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α
4. ²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β
Explanation:
1. In the first equation, Beryllium-10 isotope undergoes beta-decay, emitting a beta-particle to form boron-10 isotope. The balanced nuclear equation is given below:
¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β
2. In this reaction, silicon-34 isotope undergoes beta-decay, emitting a beta-particle to form phosphorus-34 isotope. The balanced nuclear equation is given below:
³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β
3. In this equation, platinum-192 isotope undergoes alpha-particle decay emitting an alpha-particle to form osmium-190 isotope. The balanced nuclear equation is given below:
¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α
4. In this equation, magnesium-28 isotope undergoes beta-decay, emitting a beta-particle to form aluminum-28 isotope. The balanced nuclear equation is given below:
²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β
