Answer: 600 kJ
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Explanation:
C₃H₈ (g) + 5 O₂ (g) =============== 3 CO₂ (g) + 4 H₂O (l)
Δ⁰Hf kJ/mol -104 0 -393.5 -285.8
Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104) kJ/mol
Δ⁰Hcomb = 2219.70 kJ/mol
n= m /MW MW c₃H₈ = 44.1 g/mol
n= 12 g/44.1 g/mol = 0.27 mol
then for 12 g the heat released will be
0.27 mol x 2219.70 kJ/mol = 600 KJ
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
Answer:
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Explanation:
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Answer:
Option b, The change in free energy of the reaction (ΔG)
Explanation:
Gibbs free energy is a measure of amount of usable energy in the system.
It is related with enthalpy (H), entropy (S) and temprature (T) as:
G = H - TS
The Gibbs free energy change (ΔG) provide spontaneity of a chemical reaction.
If ΔG is negative, then reaction is spontaneous that means reaction is moving towards forward direction.
If ΔG is positive, then reaction is non-spontaneous that means reaction is moving in backward direction.
If ΔG is zero, then reaction is at equilibrium.
Change in enthalpy only gives informtion about heat involed in a chemical reaction, it does not give information about direction of the reaction.
So, among the given options, option b is correct.
