Answer:
Step-by-step explanation:
Hope this helped!
<h2>~AnonymousHelper1807</h2>
1. The data is not linear. There's not a constant difference between the f(x) values. (AKA there's not a fixed slope between the data points)
2. The data is exponential, because there's a consistent ratio in the f(x) values:
189/567 = 1/3
63/189 = 1/3
21/63 = 1/3
7/21 = 1/3
Each new y-value (aka f(x)-value) is 1/3 the previous value.
Also, f(0)=567.
If we put that together, we have f(x) = 567 (1/3)^x.
Answer 5x =46 Ikdrrrrrr
Step-by-step explanation:
<span>Think of arcsin (-1/3) as an angle, and call it "theta." The the original problem becomes "find sec [ 2 theta ]"
1 1
which is the same as "find ------------------ " or --------------------------------------
cos[2 theta] (cos theta)^2 - (sin theta)^2
Recall that theta = the angle whose sine is -1/3. Thus, sin theta = -1/3 and cos theta = 2sqrt(2) / 3.
So we now have:
1
-------------------------------------------
2 sqrt(2) -1
[------------------- ]^ 2 - [ ------- ]^2
3 3
which boils down to:
1 1
----------------- = ---------------- = 9/7 (answer)
8 1 7/9
------ - --------
9 9
</span>
Answer: 428
Step-by-step explanation:
This is a substitution problems,
Just substitute for the values of x and y , multiply them out and add.
Here we go;
5x³ + 4y³
= 5(4³) + 4(3³)
= 5( 4 x 4 x 4 ) + 4( 3 x 3 x 3)
= 5 x 64 + 4 x 27
= 320 + 108 add directly or find the common factor
= 4(80 + 27)
= 4(107)
= 4 x 107
= 428
