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jek_recluse [69]
3 years ago
9

The 25 member of the reading club are buying a book to discuss at the next meeting the club leader got a special price the book

will cost 8.14 for each person how much will the 25 books cost
Mathematics
2 answers:
Pavel [41]3 years ago
5 0

8.14 times 25 = 203.5

Eduardwww [97]3 years ago
3 0

the answer is $5087.5                                    

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umka2103 [35]

Step-by-step explanation:

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a = sin46° * 12.8 = 9.20

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3 years ago
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Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

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3 years ago
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spayn [35]

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with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = \sqrt{(-1-5)^2+(1-4)^2}

   = \sqrt{(-6)^2+(-3)^2}

   = \sqrt{36+9}

   = \sqrt{45}

   = 3\sqrt{5} ← exact value

   ≈ 6.71 ( to 2 dec. places )

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3 meters below sea level represents a -3
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