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andrezito [222]
3 years ago
14

Need help with number 8

Mathematics
1 answer:
natka813 [3]3 years ago
8 0
Perimeter is 2(2x+5)+2(x-2) which is 4x+10+2x-4 which is in turn 6x+6. 6x+6 is the perimeter. Hope I helped!
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12/5 rename the fractions as mixed numbers
Alex_Xolod [135]

Answer:

2 2/5

Step-by-step explanation:

12 can go into 5 2 times with a left over of two, so it would be 2 which is 10 and a left over of two. The denominator stays the same. So it would be 2 2/5.

5 0
2 years ago
What is parallel to 2x-y=1 and contains (4, -6)? Please show your work!
Contact [7]

k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\\text{We have}\\\\k:\ 2x-y=1\ \ \ |-2x\\-y=-2x+1\ \ \ \ |\cdot(-1)\\y=2x-1\to m_1=2\\\\l:\ y=m_2x+b\\\\l\ ||\ k\iff m_2=2\\\\l:\ y=2x+b\\\\\text{The line l contains (4, -6)}\\\\\text{Put the values of coordinates to the equation of line l}\\\\-6=2(4)+b\\-6=8+b\ \ \ \ \ |-8\\b=-14\\\\Answer:\ y=2x-14\to 2x-y=14

5 0
3 years ago
Can someone help me with 3
attashe74 [19]

Area = Length x Width

72 = Length x 6

Length = 12

5 0
3 years ago
Complete the table and then graph the function.
Gekata [30.6K]

Answer:

You plug in x and solve for each value. Look at attachment for answers

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.
leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0
3 years ago
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