Explanation:
The Journal entry is shown below:-
a. Merchandise inventory Dr, $4,700
To accounts payable $4,700
(Being Purchase of merchandise is recorded)
b. Accounts payable Dr, $1,600
To Merchandise inventory $1,600
(Being Return of merchandise is recorded)
c. Accounts payable Dr, $3,100
To Merchandise inventory $31
($3,100 × 1%)
To cash account $3,069
(Being the amount paid)
Answer:
inventory impairment/cost of good sold (p/l) $500
Explanation:
IAS 2 requires that inventory be initially recognized at cost including cost of purchase and other necessary cost incurred in getting the inventory to the location where it becomes available for sale.
Subsequently, the item of inventory is carried at the lower of cost or net realizable value (NRV).
Quantity Unit Cost Unit NRV Lower of cost/NRV Amount
Model A 100 $100 $ 120 $100 $10,000
Model B 50 $50 $ 40 $40 $2,000
Model C 20 $200 $210 $200 $4,000
Adjustment required = 50 ($50 - $40)
=$500
This posted as
Debit inventory impairment/cost of good sold (p/l) $500
Credit Inventory account $500
The dimensions of the cylinder can be used to minimise cost of manufacture.
<h3>How to we find minimised cost?</h3>
Let's ignore the metal's thickness and assume that the material cost to manufacture is precisely proportionate to the surface area of a perfect cylinder.
A=2πr(r+h)
Given that V=1000=r2h and h=1000=r2, we can write
A=2πr(r+1000πr2)
A=2πr2+2000r−1
By setting the derivative to zero, we may determine the value of r that minimises A:
A′=4πr−2000r−2
0=4πr−2000r−2
2000r−2=4πr
2000=4πr3
r=500π−−−√3
r=5.419 + cm
h=1000πr2=10.838 + cm
The can with the smallest surface area has a volume of 1000 cm 3 and measures 5.419+ cm in radius and 10.838+ cm in height. The can has a surface area of 553.58 cm 2. Given a constant volume, the cylinder with diameter equal to height has the least surface area.
Can surface area (cm2) versus. radius (cm), where capacity = 1000cm 3.
Learn more about manufacturing here:
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Answer:
productivity is calculated by using formula
Explanation:
formula = total output/ total input
