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iragen [17]
3 years ago
5

Find the area of the circle with the center C (1, -2) and passes through the point (4, 2). Round your answer to the nearest tent

h.
Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

Step-by-step explanation:

r=√((4-1)²+(2+2)²)=√(9+16)=5

area of circle=π r²=3.14×5²=78.50=78.5

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In the following Earliest Start Time (EST) graph, assume each unit of time is an hour.
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Step-by-step explanation:

  • Critical Path Analysis is presented using the circle and arrow diagrams.
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3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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3 years ago
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Answer:

i think 22

Step-by-step explanation:

9*22=198

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Based on the picture, PC = PD
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