Answer:
start();
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
move();
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
move();
}
}
if(colorIs(Color.blue)){
paint(Color.red);
if(frontIsClear());
}else{
if(colorIs(Color.red)){
paint(Color.blue);
if(frontIsClear());
}
}
function start(){
}
Q. 5.1.3: Move to Wall
Ans:
function start(){
while(frontIsClear()){
move();
}
}
I apologize if its incorrect
Answer:
a. Utilization = 0.00039
b. Throughput = 50Kbps
Explanation:
<u>Given Data:</u>
Packet Size = L = 1kb = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
RTT = 20 msec
<u>To Find </u>
a. Sender Utilization = ?
b. Throughput = ?
Solution
a. Sender Utilization
<u>As Given </u>
Packet Size = L = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
Transmission Time = L/R = 8000 bits / 1 x 10⁹ bps = 8 micro-sec
Utilization = Transmission Time / RTT + Transmission Time
= 8 micro-sec/ 20 msec + 8 micro-sec
= 0.008 sec/ 20.008 sec
Utilization = 0.00039
b. Throughput
<u>As Given </u>
Packet Size = 1kb
RTT = 20ms = 20/100 sec = 0.02 sec
So,
Throughput = Packet Size/RTT = 1kb /0.02 = 50 kbps
So, the system has 50 kbps throughput over 1 Gbps Link.
The correct answer is B: ls -l.
Further Explanation:
In Linux there is a specific command needed to look at the files in a directory. In addition to using the command ls -l, you will need to use < > after the command and insert the name of the file that is being looked for. For example: ls -l <root root 2356 0600 Oct 22 lanyard>.
Each word and character has their own meaning and access information stored in the database. This will also show the users accesses permission to see the file and if needed to write over the file.
Learn more about computer commands at brainly.com/question/13338803
#LearnwithBrainly