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3241004551 [841]
3 years ago
14

Scavenging is a form of fraud in which the perpetrator uses a computer program to search for key terms in a database and then st

eal the data.
A. True
B. False
Computers and Technology
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

The given statement is False.

Explanation:

Scavenging is the process in which the person uses the following programs of the computer system because of the purpose of searching the key terms from the database but not in the intention of stealing the data of the company or an organization. That's why it is not the form of fraud. So, that's why the following statement is False.

You might be interested in
Apple was a pioneer in user interface development, introducing the _____, complete with mouse and screen icons, in the early 198
KiRa [710]

Answer:

The answer is "Option b"

Explanation:

The graphical UI is a kind of user interface, which is used in apple technology. It enables the consumers to use graphic symbols and the main symbol sound signal to communicate with electronic devices rather of text-based consumer interface, type tag commands or code navigation, and wrong option can be described as follows:

  • Option a and Option c both were wrong because the command-line interface is a text-based program, and binary line access via command line.
  • In option d, It is a text-based command, that is used to intact with the user, that's why it is wrong.
7 0
3 years ago
A database is used instead of a spreadsheet when?
Luba_88 [7]
Lists involve date with multiple themes. 
5 0
3 years ago
Write a program that prompts the user for a measurement inmeters and then converts it into miles, feet, and inches.
zubka84 [21]

Answer:

Program for measurement in meters and then converts it into miles, feet, and inches:

#include<iostream.h>

#include<conio.h>

void main()

{  float meter, mile, feet, inches;

 cout<<"enter meters";

 cin>>meters";

 feet=meter×3.2808;

 mile= meter×0.000621371;

 inches= meter×39.3701;

cout<<"Value of"<<meter<<"meter"<<"in feet is"<<feet<<"feet":

cout<<"Value of"<<meter<<"meter"<<"in mile is"<<mile<<"mile";

cout<<"Value of"<<meter<<"meter"<<"in inches is"<<inches<<"inches";

getch();

}

8 0
3 years ago
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
3 years ago
in Java programming Design a program that will ask the user to enter the number of regular working hours, the regular hourly pay
iren2701 [21]

Answer:

In Java:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

 int regularhour,overtimehour;

 float regularpay,overtimepay;

 Scanner input = new Scanner(System.in);

 

 System.out.print("Regular Hour: ");

 regularhour = input.nextInt();

 

 System.out.print("Overtime Hour: ");

 overtimehour = input.nextInt();

 

 System.out.print("Regular Pay: ");

 regularpay = input.nextFloat();

 

 System.out.print("Overtime Pay: ");

 overtimepay = input.nextFloat();

 

 float regulargross = regularhour * regularpay;

 float overtimegross = overtimehour * overtimepay;

 float totalgross = regulargross + overtimegross;

 

 System.out.println("Regular Gross Pay: "+regulargross);

 System.out.println("Overtime Gross Pay: "+overtimegross);

 System.out.println("Total Gross Pay: "+totalgross);

 

}

}

Explanation:

This line declares regularhour and overtimehour as integer

 int regularhour,overtimehour;

This line declares regularpay and overtimepay as float

 float regularpay,overtimepay;

 Scanner input = new Scanner(System.in);

 

This prompts the user for regular hour

 System.out.print("Regular Hour: ");

This gets the regular hour

 regularhour = input.nextInt();

 

This prompts the user for overtime hour

 System.out.print("Overtime Hour: ");

This gets the overtime hour

 overtimehour = input.nextInt();

 

This prompts the user for regular pay

 System.out.print("Regular Pay: ");

This gets the regular pay

 regularpay = input.nextFloat();

 

This prompts the user for overtime pay

 System.out.print("Overtime Pay: ");

This gets the overtime pay

 overtimepay = input.nextFloat();

 

This calculates the regular gross pay

 float regulargross = regularhour * regularpay;

This calculates the overtime gross pay

 float overtimegross = overtimehour * overtimepay;

This calculates the total gross pay

 float totalgross = regulargross + overtimegross;

 

This prints the regular gross pay

 System.out.println("Regular Gross Pay: "+regulargross);

This prints the overtime gross pay

 System.out.println("Overtime Gross Pay: "+overtimegross);

This prints the total gross pay

 System.out.println("Total Gross Pay: "+totalgross);

8 0
3 years ago
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