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Harrizon [31]
3 years ago
9

Plssssssss hurry, which one is my answer?

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:no cap

Step-by-step explanation:that looks complicated

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Use integer rules to evaluate: 85 + (-96) *
grin007 [14]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{ - 11}}}}}

Step-by-step explanation:

\sf{85 + ( - 96)}

Multiplying positive integer and negative integer gives a negative integer i.e ( + ) × ( - ) = ( - )

\longrightarrow{ \sf{85 - 96}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\longrightarrow{ \sf{ - 11}}

Hope I helped!

Best regards! : D

6 0
3 years ago
Please help!! asap!!! ( 10 points)
MAXImum [283]

Answer:

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Step-by-step explanation:

5 0
4 years ago
De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

7 0
3 years ago
Solve 15 and 21, will give BRAINLIST!!
xeze [42]

Answer:

Step-by-step explanation:

<h2>4/x=2/10</h2>

cross multiplication:

4*10=2*x

40=2x

x=40/2=20

<h2>w/2 = 4.5/6.8</h2>

6.8w=2(4.5)

6.8w=9

w=9/6.8=1.32352941

4 0
3 years ago
Read 2 more answers
I don’t understand this equation please help me
Reika [66]

Answer:

Evaluated, you get 4x^4

Step-by-step explanation:

Differentiated, you get 16x^3

It all depends on what you're looking for, really

8 0
3 years ago
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