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Talja [164]
3 years ago
7

Solve the following matrix system: The explanation how you did it would help! Thanks in advance!

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

X - Y =  \begin{pmatrix} 1 & 2 & 7 \\  - 1 & 3 & 5 \\ 3 & 1 & 7 \end{pmatrix} \\\\ X  +  Y =  \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} \\  adding \: both \: the \: matrices \\  \\ X   -   Y + X  +  Y \\  = \begin{pmatrix} 1 & 2 & 7 \\  - 1 & 3 & 5 \\ 3 & 1 & 7 \end{pmatrix} + \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} \\\\  2X= \begin{pmatrix} 1 + 1 & 2 + 0 & 7 + 1 \\  - 1 + 1 & 3 + 1 & 5  + 3\\ 3 - 1 & 1 + 3 & 7 + 3 \end{pmatrix} \\  \\ 2X= \begin{pmatrix} 2 & 2 & 8 \\  0 & 4 & 8\\ 2 & 4 & 10 \end{pmatrix} \\  \\ X=  \frac{1}{2} \begin{pmatrix} 2 & 2 & 8 \\  0 & 4 & 8\\ 2 & 4 & 10 \end{pmatrix}\\  \\ X=   \huge\begin{pmatrix} \frac{2}{2} & \frac{2}{2} & \frac{8}{2} \\  \\  \frac{0}{2} & \frac{4}{2} & \frac{8}{2}\\ \\  \frac{2}{2} & \frac{4}{2} & \frac{10}{2} \end{pmatrix} \\  \\  \huge  \red{X=   \begin{pmatrix} 1 & 1 & 4\\  \\ 0 & 2 & 4\\ \\  1 & 2& 5 \end{pmatrix}} \\  \\ subtracting \: the \: value \: of \: x \: from \: matrix \: (2) \\  \\ X  +  Y  - X \\ =  \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} - \begin{pmatrix} 1 & 1 & 4 \\ 0 & 2 & 4\\  1 & 2& 5 \end{pmatrix} \\  \\ Y = \begin{pmatrix} 1 - 1 & 0 - 1 & 1 - 4 \\  1  - 0& 1 - 2 & 3 - 4 \\  - 1 - 1 & 3 - 2 & 3 - 5 \end{pmatrix} \\  \\  \huge  \purple{Y = \begin{pmatrix} 0 & - 1 &  - 3 \\  1  &  - 1  &  - 1 \\  - 2 & 1 &  - 2 \end{pmatrix}}

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Papa john is 50 years old. His age is 2 years more than 3 times the age of Jimmy John. How old is Jimmy?
mojhsa [17]

Answer:

<h2>Jimmy is 16 old.</h2>

Step-by-step explanation:

J - the age of Jimmy John

50 - the age of Papa John

3J + 2 - the age of Papa John

The euaqtion:

3J + 2 = 50             <em>subtract 2 from both sides</em>

3J + 2 - 2 = 50 - 2

3J = 48          <em>divide both sides by 3</em>

3J/3 = 48/3

J = 16

4 0
3 years ago
jem pastes 21 photos and 15 postcards in a scrap album. she puts 3 items on each page. how many pages does jem fill in the scrap
ddd [48]
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6 0
3 years ago
Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0
3 years ago
Which term is correct when simplifying √128?<br><br> A.) 16<br> B.) 12<br> C.) 10<br> D.) 8√2
alina1380 [7]
When dealing with roots, we want to factor to see if it's possible

128  = 2 \times 64
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now since we're dealing with square roots, we circle every pair of numbers we see in the final factoring
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now for every circled pair, we take only 1 of the 2 circled and bring it outside
anything left uncircled stays inside the root
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= 2 \times 2 \times 2 \times \sqrt{2}

now simply multiply
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3 0
3 years ago
Did he watch the whole movie
valentinak56 [21]
No, he has not watched the whole movie. The answer would be D. he only has 2/15 to watch. 

Hope I helped!
8 0
3 years ago
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