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Talja [164]
3 years ago
7

Solve the following matrix system: The explanation how you did it would help! Thanks in advance!

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

X - Y =  \begin{pmatrix} 1 & 2 & 7 \\  - 1 & 3 & 5 \\ 3 & 1 & 7 \end{pmatrix} \\\\ X  +  Y =  \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} \\  adding \: both \: the \: matrices \\  \\ X   -   Y + X  +  Y \\  = \begin{pmatrix} 1 & 2 & 7 \\  - 1 & 3 & 5 \\ 3 & 1 & 7 \end{pmatrix} + \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} \\\\  2X= \begin{pmatrix} 1 + 1 & 2 + 0 & 7 + 1 \\  - 1 + 1 & 3 + 1 & 5  + 3\\ 3 - 1 & 1 + 3 & 7 + 3 \end{pmatrix} \\  \\ 2X= \begin{pmatrix} 2 & 2 & 8 \\  0 & 4 & 8\\ 2 & 4 & 10 \end{pmatrix} \\  \\ X=  \frac{1}{2} \begin{pmatrix} 2 & 2 & 8 \\  0 & 4 & 8\\ 2 & 4 & 10 \end{pmatrix}\\  \\ X=   \huge\begin{pmatrix} \frac{2}{2} & \frac{2}{2} & \frac{8}{2} \\  \\  \frac{0}{2} & \frac{4}{2} & \frac{8}{2}\\ \\  \frac{2}{2} & \frac{4}{2} & \frac{10}{2} \end{pmatrix} \\  \\  \huge  \red{X=   \begin{pmatrix} 1 & 1 & 4\\  \\ 0 & 2 & 4\\ \\  1 & 2& 5 \end{pmatrix}} \\  \\ subtracting \: the \: value \: of \: x \: from \: matrix \: (2) \\  \\ X  +  Y  - X \\ =  \begin{pmatrix} 1 & 0 & 1 \\  1 & 1 & 3 \\  - 1 & 3 & 3 \end{pmatrix} - \begin{pmatrix} 1 & 1 & 4 \\ 0 & 2 & 4\\  1 & 2& 5 \end{pmatrix} \\  \\ Y = \begin{pmatrix} 1 - 1 & 0 - 1 & 1 - 4 \\  1  - 0& 1 - 2 & 3 - 4 \\  - 1 - 1 & 3 - 2 & 3 - 5 \end{pmatrix} \\  \\  \huge  \purple{Y = \begin{pmatrix} 0 & - 1 &  - 3 \\  1  &  - 1  &  - 1 \\  - 2 & 1 &  - 2 \end{pmatrix}}

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