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zaharov [31]
3 years ago
9

In what ratio the mass 4m should be split so the value of gravitational force comes maximum for a fix distance d between the mas

ses?
F=G(4m-x)/r^2 G/r^2(4m-x^2)
Physics
1 answer:
amid [387]3 years ago
4 0
Let mass 4m be Z 
<span>F=G(m1*(Z-m1)/d^2 </span>
<span>Using calculus... </span>
<span>dF/dm1=0=G(Z-m1)/d^2 -m1/d^2) </span>

<span>solving for m1, </span>
<span>Z-m1-m1=0 </span>
<span>m1=Z/2 </span>

<span>So split into 2m, and2m. </span>

<span>Now if you don't know the wonderful world of calculus, then plot the following parabola, and see where it is max: </span>
<span>F=G(m1*(Z-m1)/d^2 </span>
<span>k=Z(m1)-(m1)^2</span>
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