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attashe74 [19]
2 years ago
14

Even though it's not very popular these days, I like our system . Getting together to talk about who the best candidate might be

makes me feel like we're really part of democracy. After the debate, we vote. In my state, any voter can participate. It's all pretty informal. What system for selecting party nominees does the passage describe? . Mixed primary B. Caucus C. Open primary . Closed primary
Physics
1 answer:
DaniilM [7]2 years ago
7 0

Answer:

I think it would be C: open primary

Explanation:

You might be interested in
A positive charge Q1 = 30.5 nC is located at the origin. A negative charge Q2 = -3.5 nC is located on the positive x-axis p = 3
Dmitriy789 [7]

Answer:

The points where the electric field due to the two charges are 0 include

x = 4.54 cm and x = 2.24 cm.

Explanation:

For a positive charge, the electric field is directed outward from the charge,

For a negative charge, it is directed towards it.

Since the positive charge is at the origin, the, and the negative charge is at p = 3cm on the x-axis, let the point where the electric field is 0 be x.

For ease of calculation, we will be looking for x, along the positive x-axis in between the two charges.

Electric field at a point due to a particular charge is given as

E = (kq/r²)

k = Coulomb's constant = (9.0 × 10⁹) Nm²/C²

r = distance of the point from the charge.

q = the charge

q₁ = 30.5 nC = (30.5 × 10⁻⁹) C

q₂ = -3.5 nC = (3.5 × 10⁻⁹) C

For the positive charge

E₁ = (kq₁)/x²

= (9.0 × 10⁹ × 30.5 × 10⁻⁹)/x²

E₁ = (274.5/x²) (eqn 1)

For the negative charge

E₂ = [kq₂/(x-0.03)²]

E₂ = 31.5/(x-0.03)²

E₁ + E₂ = 0

(274.5/x²) - [31.5/(x-0.03)²] = 0 (with the assumption that the point is to the right of both charges)

(274.5/x²) =-[31.5/(x-0.03)²]

274.5 (x-0.03)² = 31.5x²

274.5 (x² - 0.06x + 0.0009) = 31.5x²

274.5x² - 16.47x + 0.24705 = 31.5x²

243x² - 16.47x + 0.24705 = 0

Solving this equation

x = 0.0454 m or x = 0.0224 m

So, the points where the electric field due to the two charges are 0 include

x = 4.54 cm and x = 2.24 cm.

Hope this Helps!!!

7 0
3 years ago
Read 2 more answers
Calculate the energy absorbed when 13 kg of liquid water raises from 18°C to 100°C and then boils at 100°C.
Cloud [144]

Answer:

the energy absorbed is 4.477 x 10⁶ J

Explanation:

mass of the liquid, m = 13 kg

initial temperature of the liquid, t₁ = 18 ⁰C

final temperature of the liquid, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg⁰C

The energy absorbed is calculated as;

H = mcΔt

H = mc(t₂ - t₁)

H = 13 x 4,200(100 - 18)

H = 4.477 x 10⁶ J

Therefore, the energy absorbed is 4.477 x 10⁶ J

5 0
3 years ago
You place a box weighing 253.1 N on an inclined plane that makes a 39.7◦ angle with the horizontal.
Masja [62]

Answer:

Explanation:

The weight of the box is

W = 253.1N

Weight is on an incline plane

θ = 39.7°

The weight of an object is always acting downward

So, the weight makes an angle of 39.7° with the vertical component

Then, it's horizontal component is

Wx = W•Sinθ

Wx = 253.1 × Sin 39.7°

Wx = 161.67 N

The horizontal component of the weight is 161.67N

This is the force acting down the plane.

Check attachment

7 0
3 years ago
You happen to know that the coefficient of static friction between your patio table and the ground is 0.42. You decide you want
Deffense [45]

Answer:

If the force applied is larger than 185.2 N, yes.

Explanation:

In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

F_f = \mu mg

where

\mu=0.42 is the coefficient of static friction

m=45 kg is the mass of the table

g=9.8 m/s^2 is the gravitational acceleration

Substituting,

F_f=(0.42)(45 kg)(9.8 m/s^2)=185.2 N

So, we are able to move the table if we push with a force larger than 185.2 N.

4 0
3 years ago
The hydrogen atom, changing from its first excited state to its lowest energy state, emits light with a wavelength of 122 nm. Th
tatyana61 [14]

Answer:

true b and c

Explanation:

n the electromechanical transitions of the atoms the relationship must be fulfilled

        \frac{x}{\lambda } = R (1 / nf - 1 / no²)

where for the final state nf = 1 giving in the case of hydrogen the Lymma series whose smallest wavelength is lam = 122 nm with nf = 1 and there are a series of spectral lines for each value of n of the final state

in the case of sodium so well it has a transition from an excited state to the kiss state (bad)

Now let's review the different proposals

a) False. The electronic potential for sodium is much lower than for hydrognosia

b) True

c) True

d) true

8 0
3 years ago
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