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attashe74 [19]
2 years ago
14

Even though it's not very popular these days, I like our system . Getting together to talk about who the best candidate might be

makes me feel like we're really part of democracy. After the debate, we vote. In my state, any voter can participate. It's all pretty informal. What system for selecting party nominees does the passage describe? . Mixed primary B. Caucus C. Open primary . Closed primary
Physics
1 answer:
DaniilM [7]2 years ago
7 0

Answer:

I think it would be C: open primary

Explanation:

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A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
Alex73 [517]

Answer:

Explanation:

Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²

According to the Gauss theorem,

Electric field due to the sheet is given by

E = \frac {\sigma }{2\epsilon _{0}}

E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}

E = 5.08 x 10^5 N/C

7 0
3 years ago
An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e
VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

PART A) We will begin by finding the two net distances.

r = \frac{8.26}{2} = 4.13m

And the distance 'd' is

d = lsin\theta

d = 1.14 sin 16.2\°

d = 0.318m

Through the free-body diagram the tension components are given by

Tcos\theta = mg

Tsin\theta = \frac{mv^2}{R}

Here we can watch that,

R = r+d

Dividing both expression we have that,

tan\theta = \frac{v^2}{Rg}

Replacing the values,

tan(16.2) = \frac{v^2}{(4.13+0.318)(9.8)}

v = 4.83371m/s

PART B) Using the vertical component we can find the tension,

Tcos\theta = mg

T = \frac{mg}{cos\theta}

T = \frac{(10+26.2)(9.8)}{cos(16.2)}

T = 369.42N

6 0
3 years ago
A vibrating object produces periodic waves with a wavelength of 53 cm and a frequency of 15 Hz. How fast do these waves move awa
DerKrebs [107]

Answer:

v = 7.95 m/s

Explanation:

Given that,

Wavelength of a wave, \lambda=53\ cm=0.53\ m

Frequency of a wave, f = 15 Hz

We need to find the speed of the wave. The speed of a wave is given by :

v=f\lambda\\\\v=15\ Hz\times 0.53\ m\\\\v=7.95\ m/s

So, the wave move with a speed of 7.95 m/s.

5 0
3 years ago
Is it true or not true
maria [59]

Answer:

true

Explanation:

6 0
3 years ago
45 grams in kilo grams
Hunter-Best [27]

Answer:

0.045 kg

Explanation:

1000 grams = 1kg

7 0
3 years ago
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