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3 years ago

13

A drop of oil of volume

- 10} " alt=" {10}^{ - 10} " align="absmiddle" class="latex-formula">

1 answer:

Monica [59]3 years ago

8 0

Answer:

$\frac{1}{10^{10}}\\$

Explanation:

$10^{-10}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\\\10^{-10}=\\\frac{1}{10^{10}}\\\\\left(\mathrm{Decimal:\quad }\:0.0000000001\right)$

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The initial speed of a body is 4.24 m/s. What is its speed after 2.91 s if it accelerates uniformly at -1.76 m/s2

shutvik [7]

Initial velocity=u=4.24m/s
Time=t=2.91s
Acceleration=a=-1.76m/s^2
Final velocity=v

Using 1st equation of kinematics

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=4.24+2.91(-1.76)$

$\\ \sf\longmapsto v=|4.24-5.12|$

$\\ \sf\longmapsto v=0.8m/s$

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3 years ago

What concerns people in regards to<br> the federal government?

inysia [295]

Answer:

Mulitple Changes.

Explanation:

Most people want something to be done, and never change again. But some others do, since they have there own beliefs. Alot of people are concerned about tax rates, taxes, nationial polices, own beliefs. People have there own beliefs and when someone is elected into the federal Government, they have there own Beliefs (Mostly Republican Or Democrate). People go against on what they dont think and go with what they think. At the end whoever sways the people on who to believe and vote for, Is elected.

3 0

3 years ago

A particle of mass m collides with a second particle of mass m. Before the collision, the first particle is moving in the x-dire

oee [108]

Answer:

a) v, v

b) 2mv^2

c) Elastic collion

Explanation:

(a) The velocity of the second particle after the collision is (v2x,v2y)=(v,−v). From momentum conservation in x-direction

Here x, y represent direction.They are not variable. 1 and 2 represent before and after.

2vm=v1xm+v2xm, we find v1x=v.

From momentum conservation in y-direction

0 =v1ym+v2ym, we findv1y=v.

(b) By energy conservation principle

Before: K=1/2m(2v)^2=2mv^2.

After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2

(c) The collision is elastic

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3 years ago

0.16 mol of argon gas is admitted to an evacuated 70 cm^3 container at 30°C. The gas then undergoes an isothermal expansion to a

Semmy [17]

Answer:

The final pressure of the gas is 9.94 atm.

Explanation:

Given that,

Weight of argon = 0.16 mol

Initial volume = 70 cm³

Angle = 30°C

Final volume = 400 cm³

We need to calculate the initial pressure of gas

Using equation of ideal gas

$PV=nRT$

$P_{i}=\dfrac{nRT}{V}$

Where, P = pressure

R = gas constant

T = temperature

Put the value in the equation

$P_{i}=\dfrac{0.16\times8.314\times(30+273)}{70\times10^{-6}}$

$P_{i}=5.75\times10^{6}\ Pa$

$P_{i}=56.827\ atm$

We need to calculate the final temperature

Using relation pressure and volume

$P_{2}=\dfrac{P_{1}V_{1}}{V_{2}}$

$P_{2}=\dfrac{56.827\times70}{400}$

$P_{2}=9.94\ atm$

Hence, The final pressure of the gas is 9.94 atm.

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3 years ago

At the _______________ point, the particles in an object have not kinetic energy

Brums [2.3K]

The freezing point ..... :)

4 0

3 years ago