Question

A plane flies over point A going 300 m/s, 10 seconds later it flies over point B going 260m/s. 45 seconds after that it is going 350m/s. What is the plains acceleration at points B, and C? (Hint: Solve for both accelerations) (Show all work!)

Answer 1

Answer:

$\boxed{ \text{-4 m/s}^{2} \text{ at Point B; 2 m/s}^{2} \text{ at Point C. }}$

Step-by-step explanation:

Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).

$a = \frac{ \Delta v }{ \Delta t } = \frac{v_{2} - v_{1} }{t_{2} - t_{1}}$

1. Acceleration at Point B

$a = \frac{260 - 300 }{10 - 0} = \frac{-40 }{ 10} = \text{-4 m/s}^{2}$

$\boxed{\textbf{The acceleration is -4 m/s}^{2}.}$

2. Acceleration at Point C

$a = \frac{350 - 260 }{45 - 0} = \frac{90 }{ 45} = \text{2 m/s}^{2}$

$\boxed{\textbf{The acceleration is 2 m/s}^{2}.}$