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Olin [163]
3 years ago
14

A plane flies over point A going 300 m/s, 10 seconds later it flies over point B going 260m/s. 45 seconds after that it is going

350m/s. What is the plains acceleration at points B, and C? (Hint: Solve for both accelerations) (Show all work!)
Mathematics
1 answer:
iogann1982 [59]3 years ago
7 0

Answer:

\boxed{ \text{-4 m/s}^{2} \text{ at Point B; 2 m/s}^{2} \text{ at Point C. }}\\

Step-by-step explanation:

Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).

a = \frac{ \Delta v }{ \Delta t } = \frac{v_{2} - v_{1} }{t_{2} - t_{1}} \\

1. Acceleration at Point B

a = \frac{260 - 300 }{10 - 0} = \frac{-40 }{ 10} = \text{-4 m/s}^{2}\\

\boxed{\textbf{The acceleration is -4 m/s}^{2}.}\\

2. Acceleration at Point C

a = \frac{350 - 260 }{45 - 0} = \frac{90 }{ 45} = \text{2 m/s}^{2}\\

\boxed{\textbf{The acceleration is 2 m/s}^{2}.}\\

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