the solution for the inequalities 5m - 2 ≤-14 or -2m ≤ -15 is m ≤ - 2.4 or m ≥ 7.5.
First inequality:
5m - 2 ≤ - 14
Add 2 to both the sides:
5 m - 2 + 2 ≤ - 14 + 2
5 m ≤ - 12
Divide both sides by 5:
5 m / 5 ≤ - 12 / 5
m ≤ - 2.4
Other inequality:
-2m ≤ -15
Divide both sides by 2:
-m ≤ -7.5
m ≥ 7.5
So, we get:
m ≤ - 2.4 or m ≥ 7.5
Therefore, we get that, the solution for the inequalities 5m - 2 ≤-14 or -2m ≤ -15 is m ≤ - 2.4 or m ≥ 7.5.
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Solve the inequalities:
5m - 2 ≤-14 or -2m ≤ -15
0.005 would be 5/1000 because how I know if it is 10ths or 100ths or 1000ths I count all the number on the right side of the decimal, hoped this could help!
1X2
b32
Eagles
for the first page
To obtain the probability of obtaining heads at least 3 times out of 5 times we recall that in her simulation <span>she
assigned odd digits to represent heads and even digits to represent
tails. Thus, we count the simulated numbers to see in how many numbers
do we have 3 or more odd digits.
Below, the simulated numbers with 3 or more odd digits are bolded.
</span> <span>32766 53855 34591 27732
47406 31022 25144 72662
03087 35521 26658 81704
56212 72345 44019 <span>65311
</span>
We have 6 simulated numbers having 3 or more odd digits.
Therefore, </span><span>P("heads" at least 3 out of 5 times) = 6 / 16 = 3 / 8.</span>