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Natali5045456 [20]
3 years ago
8

F(x)=[3x-4] absolute value​

Mathematics
2 answers:
VLD [36.1K]3 years ago
4 0
I think it might be X > 1
Alinara [238K]3 years ago
3 0

Answer:

x≥1

Step-by-step explanation:

x has to be bigger than 1 or equal to 1.

Because if it is something smaller than that, then the answer becomes negative, which is not allowed. Absolute value always give positive answers!

Hope this helps!

Mark brainliest if you think I helped! Would really appreciate!

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Clear<br>The perimeter of a regular octagon is 88 mm. How long is each side?​
Colt1911 [192]

Answer:

11 mm

Step-by-step explanation:

An octagon has 8 sides. This mean that we do 88 divided by 8 to get the length of each side which is 11 mm.

3 0
3 years ago
A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len
Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

Area = 135yd^2

L=3W - 12

Required

Determine the length of the rectangle:

Area is calculated as thus:

Area = L * W

Substitute 3W - 12 for L and 135 for Area

135= (3W - 12) * W

135= 3W^2 - 12W

Reorder:

3W^2 - 12W - 135= 0

Divide through by 3

W^2 - 4W - 45 = 0

Expand:

W^2  - 9W + 5W - 45 = 0

W(W  - 9) + 5(W - 9) = 0

(W + 5)(W-9) = 0

W + 5 = 0 or W - 9 = 0

W = -5 or W = 9

But width can't be negative

So:

W = 9

Recall that: L=3W - 12

L = 3 * 9 - 12

L = 15

<em>Hence, the length 15 yards</em>

4 0
3 years ago
Find an equation of the sphere with center (4, −12, 8) and radius 10. use an equation to describe its intersection with each of
xxMikexx [17]
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36 Intersection in xz-plane: DNE Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84 The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin: x^2 + y^2 + z^2 = 10^2 Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2 (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100 Might as well deal with that double negative for y, so (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 And we have the desired equation. Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane: xy-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (-8)^2 = 100 (x - 4)^2 + (y + 12)^2 + 64 = 100 (x - 4)^2 + (y + 12)^2 = 36 xz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + 12^2 + (z - 8)^2 = 100 (x - 4)^2 + 144 + (z - 8)^2 = 100 (x - 4)^2 + (z - 8)^2 = -44 And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units. yz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (-4)^2 + (y + 12)^2 + (z - 8)^2 = 100 16 + (y + 12)^2 + (z - 8)^2 = 100 (y + 12)^2 + (z - 8)^2 = 84</span>
6 0
3 years ago
What is the angle of rotation of the image?<br>A. 60°<br>B. 90°<br>C.120°<br>D. 180°<br>​
lisov135 [29]

Answer:

It would be great if you would provide the image itself. I will totally answer your question.

4 0
3 years ago
Solve for x Enter the solution from least to greatest (x+6)(-x+1)=0
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

x + 6 = 0

x = -6

-x + 1 = 0

-x = -1

x = 1

x = -6, 1

3 0
3 years ago
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