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3 years ago

Two characteristics of radiowaves

1 answer:

4 0

Radio waves have the same velocity as any other electromagnetic wave, which is the speed of light (300 000km/second). ... Radio waves have the longest wavelength in the whole electromagnetic spectrum. Gamma rays have the highest frequency and the shortest wavelength. The shorter the wavelength, the higher the frequency.

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Find a total pressure of the gas mixture that contains forecast is with partial pressure of 5.00 kPa, 4.56 kPa 356 kPa and 678KP

Orlov [11]

Answer: 1044 kPa

Explanation: To find the total pressure of a system, you add up all the partial pressures. 5.00+4.56+356+678=1043.56, but since you need to account for significant figures it is 1044.

In addition, the amount of significant figures is the number with the smallest amount of decimal places. In this case you have no decimal places, since 356 and 678 have no decimal places. Remember that for the numbers 0-4 you round down and 5-9 you round up.

7 0

3 years ago

Tim and Jim finished their lab experiment earlier than their classmates. What should they do while they wait for the others to f

Alisiya [41]

The answer to your question is,

C. Look over their answers to the lab questions and check for errors.

-Mabel <3

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4 years ago

How could you have used the color change property of iron (III) chloride to monitor when the reaction had reached completion?

Tresset [83]

What reaction are you referring to

7 0

3 years ago

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

Help me pleaseʕ ꈍᴥꈍʔ

vodomira [7]

Answer:

(a) All are correct

Explanation:

catalyst a substance which speeds up a chemical reaction and remains itself unchanged.

example: Iron used in Haber process for the manufacture of ammonia.

5 0

3 years ago

Read 2 more answers

Two characteristics of radiowaves​

Two characteristics of radiowaves