What is the percent composition of hydrogen (H) in benzene (C6H6)?
2 answers:
Answer : The percent composition of hydrogen in benzene is, 7.69 %
Explanation: Given,
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
First we have to calculate the molar mass of benzene.
Molar mass of benzene =
Now we have to calculate the percent composition of hydrogen in benzene.
As we now that there are 6 number of carbon atoms and 6 number of hydrogen atoms.
The mass of hydrogen =
Formula used :
Now put all the given values in this formula, we get the percent composition of hydrogen in benzene.
Therefore, the percent composition of hydrogen in benzene is, 7.69 %
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Answer: 4.15234 m
512 g H2O * = 0.512 kg H2O
Nitric Acid: HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol
H = 1.008 g/mol
N = 14.007 g/mol
O3 = 3*15.999
134 g HNO₃ * = 2.126 mol
m = = 4.15234 m
Answer: -
If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.
Explanation: -
Density of the gasoline = 0.77 kg / liter
Volume of the tank containing the gasoline = 80 liter.
Mass of gasoline produced from each tank
= Volume of the tank containing the gasoline x Density of the gasoline
= x 80 liter
= 61.6 kg
Chemical formula of gasoline = C₈H₁₈
Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol
Number of moles of C₈H₁₈ = x 1 mol
= 0.54 mol of C₈H₁₈
The chemical equation for the burning of gasoline is
2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
From the balanced equation we see
2 mol of C₈H₁₈ gives 16 mol of CO₂
0.54 mol of C₈H₁₈ gives mol of CO₂
= 4.32 mol of CO₂
Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol
Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂
=
= 259.2 g
=
= 0.259 Kg
= 0.26 kg rounded off to 2 significant figures.
Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.
Answer:
pill need to taken for completing dosage of
mg
Explanation:
Total dosage of medicine to be taken in a day
mg
Total weight of one pill mg
Number of pills required is equal to total dosage of medicine divided by the weight of one pill.
Hence,
Number of pills