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Bumek [7]
3 years ago
6

When burning methane gas, which outcome best demonstrates the law of conservation of mass?

Chemistry
1 answer:
Tju [1.3M]3 years ago
3 0

Answer  Option D

Counting the  number of atoms each side of the equation shows that the numbers balance.

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A 40.5 g sample of aluminum is cooled 7.5°C. The specific heat capacity of aluminum is
sweet-ann [11.9K]
Q=mc\Delta T
Q= 40.5g x 0.900 J/g degree Celsius x 7.5
Q= 273.4 J.
Even if it is cooled , we use the same temperature as heating it.
3 0
3 years ago
Which of the following best accounts for the difference in mutagenic activity between PAHs and PAHs plus liver preparation?
guapka [62]

Answer: C

Explanation:

Some poly nuclear aromatic hydrocarbons are not carcinogenic in themselves. However, when these are made to interact with living cells, enzymes in the cells could convert the polynuclear aromatic hydrocarbon into a carcinogenic material such as benzo-[a]-pyrene. This can now interact adversely with the deoxyribonucleic acid of living cells leading to genetic mutation, that is, irreversible changes in the genes of organisms.

7 0
3 years ago
2C3H7OH + 9O2 -> 6CO2 + 8H2O
MAVERICK [17]

Answer:

Up to 18\; \rm mol \rm CO_2.

Explanation:

The equation for this reaction: 2\; \rm C_3 H_7 OH + 9\; O_2 \to 6\; CO_2 + 8\; H_2O is indeed balanced.

Notice that the coefficient of \rm C_3 H_7 OH is 2 while that of \rm CO_2 is 6.

Therefore, each unit of this reaction would consume 2 units of \rm C_3H_7OH while producing 6 units of \rm CO_2. In other words, this reaction would produce three times as much \rm CO_2\! as it consumes \rm C_3H_7OH\!.

If all that 6\; \rm mol of \rm C_3H_7OH molecules are actually consumed through this reaction, three times as many \rm CO_2 molecules would be produced. That corresponds to 3 \times 6\; \rm mol = 18\; \rm mol of \rm CO_2\! molecules.

6 0
2 years ago
An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it
Lera25 [3.4K]

Answer:

In full volume it contain 0.12 moles.

Explanation:

Given data:

Total volume= Vt = 2.9 L

Decreased volume= Vd = 1.2 L

Number of moles of air present in decreased volume= n = 0.049 mol

Number of moles of air in total volume= n = ?

Solution:

Formula:

Vt/ Vd = n (in total volume) /n ( decreased volume)

2.9 L / 1.2 L = X / 0.049 mol

2.42 = X / 0.049 mol

X = 2.42 × 0.049

X = 0.12 mol

6 0
3 years ago
The answer to this question
Ulleksa [173]

Hey there!

Oxygen needs two bonds to have a valence orbital of s²p⁶.

In a hexanal molecule, oxygen has a double bond with one carbon atom.

A double bond is when two pairs of electrons are being shared.

So your answer is b. 2.

Hope this helps!  

7 0
3 years ago
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