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shusha [124]
3 years ago
15

Assume that

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

D - It is impossible to make a judgment with the given information.

Step-by-step explanation:

The fact that 1200 births were randomly selected and only 599 of such picks are girls does not give enough information on whether the birth is significantly high, low or neither. We must have other information to test for significance of the births proportion.

All we know is that;

Proportion of girls birth (p) = 599/1200 = 0.499. And by default, the proportion of male births (q) will be 1-p = 1-0.499 = 0.501.

If we examine the proportion closely, there seems to be no significant difference in the birth proportion.

Having said this, we cannot really imply that, the number of girls is significantly high. Or the number of girls is neither significantly low nor significantly high. Or the number of girls is significantly low.

The best subjective submission will be that, <em>there is no significant difference between girls birth and males birth.</em> The question of high or low (an alternative hypothesis) requires some further statistical test and this question does not provide further details.

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ivanzaharov [21]

Answer:

x=2.4650

Step-by-step explanation:

I assume that you mean 3^x=15

so let s use the ln() function

ln(3^x)= xln(3)=ln(15)

so x = ln(15)/ln(3)

x = 2.4650

4 0
3 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

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3 years ago
HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined​
tiny-mole [99]

Answer: Any real number x as long as x \ne 0 and x \ne -\frac{2}{3}

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

x = 0 or 3x+2 = 0 .... zero product property

x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x)  will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

7 0
3 years ago
A basketball player has made​ 70% of his foul shots during the season. If he shoots 3 foul shots in​ tonight's game, what is the
yulyashka [42]

Answer:

There is a 34.3% probability that he makes all of the​ shots.

Step-by-step explanation:

For each foul shot that he takes during the game, there are only two possible outcomes. Either he makes it, or he misses. This means that we use the binomial probability distribution to solve this problem.

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The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 3, p = 0.7

What is the probability that he makes all of the​ shots?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.7)^{3}.(0.3)^{0} = 0.343

There is a 34.3% probability that he makes all of the​ shots.

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