Answer:
The width of the piece of construction paper is 6.75 inches.
Step-by-step explanation:
The area of the paper = 
sq inches
The length of the paper = 
in
Let the width of the paper = w inches
Now, AREA OF THE PAPER = LENGTH x WIDTH
or, 65.25 sq. inches = 9. 66 in x w in
⇒ 65.25 = 9.66 x w
or, 
or, w = 6. 75 inches
Hence, the width of the piece of construction paper is 6.75 inches.
Answer:
y' = 9x^2 + 8x^-5
Step-by-step explanation:
General Principle
y' = ax^b
y' = a*b * x^(b-1)
Solution
3x^3 = 3*3x^(3-1)
3x^3 = 9x^2
-2x^-4 = -2*-4 x ^(-4 - 1)
-2x^-4 = 8 x ^-5
Answer
y' = 9x^2 + 8x^-5
Answer:
Step-by-step explanation:
Remember 
You are given the fraction 
First, multiply the numerator and the denominator by -2-3i:
This gives you 13 in denominator, now multiply two complex numbers in numerator:
Thus, the initial fraction is
Answer:
c
Step-by-step explanation:
