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makvit [3.9K]
2 years ago
10

Review the steps of the proof.

Mathematics
2 answers:
lana [24]2 years ago
7 0

Answer:

steps 2 and 3 must be switched

Step-by-step explanation:

e2020

raketka [301]2 years ago
6 0

Answer:

C. Steps 2 and 3 must be switched.

Step-by-step explanation:

edge yuh yuhhhh

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What is the equation of the line that goes through the points (4,-1) and<br> (2,3)?
Arturiano [62]

Answer:

<u>y = -2x + 7</u>

Explanation:

<em><u>y = mx + b</u></em>

<em><u /></em>

<em>m = slope</em>

<em>b = y-intercept</em>

<em>y = a given y coordinate</em>

<em>x = a corresponding x coordinate</em>

<em />

First, we need to find the slope (m).

1) (4, -1)

2) (2/3)

m = slope = \frac{y_2-y_1}{x_2-x_1} = \frac{3-(-1)}{2-4} = \frac{4}{-2} = -2

plug in the values to the equation <u>y = mx + b</u>

<u />

-1 = -2(4) + b

-1 = -8 + b

7 = b

now, we can substitute in m and b into the equation y = mx + b

<u><em>y = -2x + 7</em></u>

5 0
3 years ago
Help help help help help help
Orlov [11]
Answer: A. 12, 12, 36
I hope this helps you
8 0
3 years ago
Read 2 more answers
Please help me please​
baherus [9]

Answer:

The answer is C

4 0
3 years ago
A box contains $7.05 in nickels, dimes, and quarters. There are 42 coins in all, and the sum of the numbers of nickels and dimes
german
I BELIEVE that there are 22 quarters, 13 dimes, and 7 nickels I’m super super sorry if wrong
3 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
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