We are given the acceleration of the bus as a function of time:
a(t) = 1.2t
Let the velocity also be a function of time v(t).
Since a(t) is the change of v(t) over time, we can use the fundamental theorem of calculus to determine the velocity at t = 2s, or v(2), given that:
a(t) = 1.2t
v(1) = 5
v(2) - v(1) = 
v(2) - 5 = 
v(2) - 5 = 0.6t² evaluated between t = 1 and t = 2
v(2) - 5 = 0.6(4) - 0.6(1)
v(2) = 1.8 + 5
v(2) = 6.8m/s
Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.
<h3>What are orbitals?</h3>
Orbital is the place around nucleus where mostly the electrons are present. There are four types of orbitals are present, s, p, d, and f.
The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.
Thus, two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.
Learn more about orbitals
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Answer:
A
Explanation:
Voltage, V = Current, I x Resistance, R (V is directly proportional to I where R is constant of proportionality)
This means that when Voltage is increased, Current increases and when voltage is decreased, current decreases (and the inverse is true). Through all this though, resistance remains constant regardless.
A particle has centripetal acceleration whenever it's a making a turn of radius R. If the particle is moving at a constant tangential speed v throughout the turn, then the magnitude of centripetal acceleration is
v²/R
If the particle is following a uniformly circular path, then it moves in a circle of radius R and travels a distance equal to its circumference, 2πR. Let T be the time it takes to complete one such loop. Then the entire circle is traversed with speed v = 2πR/T, so that the centripetal acceleration is also given by
v²/R = (2πR/T)²/R = 4π²R/T²
