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Whitepunk [10]
3 years ago
10

The heating curve of an ice-water mixture that is slowly heated to 125°C contains three sloped and two level portions. What do t

he three sloped portions in the graph represent?
Physics
2 answers:
marin [14]3 years ago
7 0

Answer:

Explanation:

Hi there,

To get started, please recall what heating curves are, latent heat, and enthalpy of phase changes (vaporization, fusion).

In a heating curve for ice water, temperature is the dependent variable (y-axis) and heat or time elapsed is independent variable (x-axis). There are three sloped portions. These sloped portions are showing where the <u>mixture is not changing phase, and is in a specific phase.</u> (solid first, then liquid then gas).

The reason is because the addition of more heat in time is causing the temperature to rise, so the mixture is getting "hotter." The temperature is still rising, yet the mixture is still in the current phase (depending on where you are referencing on the curve).

The two leveled portions are the process of melting (first leveled) and boiling (second leveled). The reason they are horizontal is because the addition of heat is not causing temperature to go up. The molecules are in the process of distributing heat in a different form by changing the mixtures entire structure (AKA phase), and so they are flat because the average kinetic energy from heat is being used change phase.

If you liked this solution, hit Thanks or leave a Rating!

thanks,

Travka [436]3 years ago
3 0

Answer:

D. phase change

Explanation:

usa test prep

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A gas has a pressure of 48atm in a 15.5L container. It was found that at 25∘C the gas occupied a volume of 25L and had a pressur
EleoNora [17]

Answer:

130.165636364°C

Explanation:

P = Pressure

V = Volume

n = Number of moles

R = Gas constant = 0.082 L atm/mol K

From ideal gas law we have

PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{22\times 25}{0.082\times (25+273.15)}\\\Rightarrow n=22.496451696\ moles

PV=nRT\\\Rightarrow T=\dfrac{PV}{nR}\\\Rightarrow T=\dfrac{48\times 15.5}{22.496451696\times 0.082}\\\Rightarrow T=403.315636364\ K

The initial temperature is 403.315636364-273.15=130.165636364\ ^{\circ}C

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NO LINKS PLEASE HELP The Spring Tide is found during which moon phases?
cestrela7 [59]

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Explanation:

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2 years ago
What does it mean to say that a wave is a cyclic, or periodic, disturbance
Ivenika [448]

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So basically it is a flowing energy that flows into the medium and hence medium particles start oscillating about their mean position to and fro.

This motion of medium particles or this to and fro motion is about their mean position and this will always be cyclic or periodic motion

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For an example

y = A sin(\omega t + kx + \phi)

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Now we can see that this disturbance depends upon the sine function and it will repeat its same position after every 2 pi time interval as it is cyclic function for this value

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A person travels by car from one city to another with differem constan1 speeds between pairs of cities. She drives for 30.0 min
Montano1993 [528]

Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

v_1=89km/h

t_1=30min

v_2=100km/h

t_2=12min

v_3=40km/h

t_3=45 min

Time spend on eating lunch and buying ga=15 min.

a.Total time=30+12+45+15=102 minute=\frac{102}{60}=1.7 hour

1 hour=60 minutes

Distance=speed\times time

d_1=v_1\times t_1=80\times\frac{30}{60}=40km

d_2=100\times \frac{12}{60}=20 km

d_3=40\times \frac{45}{60}=30 km

Total distance=d_1+d_2+d_3=40+20+30=90km

Average speed=\frac{total\;speed}{total\;time}

Using the formula

Average speed=\frac{90}{1.7}=52.9Km/h

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4 0
3 years ago
On the sonometer shown below, a horizontal cord of length 5 m has a mass of 1.45 g. When the cord was plucked the wave produced
Korolek [52]

Answer:

(a) T = 0.015 N

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Explanation:

(a) T = 0.015 N

First, we will find the speed of waves:

v =f\lambda

where,

v = speed of wave = ?

f = frequency = 120 Hz

λ = wavelength = 6 cm = 0.06 m

Therefore,

v = (120 Hz)(0.06 m)

v = 7.2 m/s

Now, we will find the linear mass density of the coil:

\mu = \frac{m}{l}

where,

μ = linear mass density = ?

m = mass = 1.45 g = 1.45 x 10⁻³ kg

l = length = 5 m

Thereforre,

\mu = \frac{1.45\ x\ 10^{-3}\ kg}{5\ m}\\\\\mu = 2.9\ x\ 10^{-4}\ kg/m

Now, for the tension we use the formula:

v = \sqrt{\frac{T}{\mu}}\\\\7.2\ m/s = \sqrt{\frac{T}{2.9\ x\ 10^{-4}\ kg/m}}\\\\(51.84\ m^2/s^2)(2.9\ x\ 10^{-4}\ kg/m) = T

<u>T = 0.015 N</u>

<u></u>

(b)

The mass to be hung is:

T = Mg\\\\M = \frac{T}{g}\\\\M = \frac{0.015\ N}{9.8\ m/s^2}\\\\

<u>M = 1.53 x 10⁻³ kg = 1.53 g</u>

4 0
3 years ago
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