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Whitepunk [10]
3 years ago
10

The heating curve of an ice-water mixture that is slowly heated to 125°C contains three sloped and two level portions. What do t

he three sloped portions in the graph represent?
Physics
2 answers:
marin [14]3 years ago
7 0

Answer:

Explanation:

Hi there,

To get started, please recall what heating curves are, latent heat, and enthalpy of phase changes (vaporization, fusion).

In a heating curve for ice water, temperature is the dependent variable (y-axis) and heat or time elapsed is independent variable (x-axis). There are three sloped portions. These sloped portions are showing where the <u>mixture is not changing phase, and is in a specific phase.</u> (solid first, then liquid then gas).

The reason is because the addition of more heat in time is causing the temperature to rise, so the mixture is getting "hotter." The temperature is still rising, yet the mixture is still in the current phase (depending on where you are referencing on the curve).

The two leveled portions are the process of melting (first leveled) and boiling (second leveled). The reason they are horizontal is because the addition of heat is not causing temperature to go up. The molecules are in the process of distributing heat in a different form by changing the mixtures entire structure (AKA phase), and so they are flat because the average kinetic energy from heat is being used change phase.

If you liked this solution, hit Thanks or leave a Rating!

thanks,

Travka [436]3 years ago
3 0

Answer:

D. phase change

Explanation:

usa test prep

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Each year, an average person in the United States is exposed to a radiation level of _____.
Anna11 [10]

Answer:

The correct answer is 0,2 rems

Explanation:

People are exposed to natural sources of radiation all the time. According to recent estimates, the average person in the United States receives an effective dose of approximately 3 mSv per year of natural radiation, which is equivalent to 0.3 rems. This amount includes cosmic radiation from outer space and is average because it varies depending on the region people are in.

The amount of radiation for a chest x-ray of an adult (0.01 rems) is approximately equal to 10 days of natural radiation to which we are all exposed every day.

Have a nice day!

3 0
3 years ago
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
S_A_V [24]

Answer:

Given:

Thermal Kinetic Energy of an electron, KE_{t} = \frac{3}{2}k_{b}T

k_{b} = 1.38\times 10^{- 23} J/k = Boltzmann's constant

Temperature, T = 1800 K

Solution:

Now, to calculate the de-Broglie wavelength of the electron, \lambda_{e}:

\lambda_{e} = \frac{h}{p_{e}}

\lambda_{e} = \frac{h}{m_{e}{v_{e}}              (1)

where

h = Planck's constant = 6.626\times 10^{- 34}m^{2}kg/s

p_{e} = momentum of an electron

v_{e} = velocity of an electron

m_{e} = 9.1\times 10_{- 31} kg = mass of electon

Now,

Kinetic energy of an electron = thermal kinetic energy

\frac{1}{2}m_{e}v_{e}^{2} = \frac{3}{2}k_{b}T

}v_{e} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{e}}}

}v_{e} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{9.1\times 10_{- 31}}}

v_{e} = 2.86\times 10^{5} m/s                    (2)

Using eqn (2) in (1):

\lambda_{e} = \frac{6.626\times 10^{- 34}}{9.1\times 10_{- 31}\times 2.86\times 10^{5}} = 2.55 nm

Now, to calculate the de-Broglie wavelength of proton, \lambda_{e}:

\lambda_{p} = \frac{h}{p_{p}}

\lambda_{p} = \frac{h}{m_{p}{v_{p}}                             (3)

where

m_{p} = 1.6726\times 10_{- 27} kg = mass of proton

v_{p} = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T

}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}

}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}

v_{p} = 6.674\times 10^{3} m/s                               (4)                    

Using eqn (4) in (3):

\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm

7 0
3 years ago
While spinning down from 500 rpm to rest, a flywheel does 3.9 kj of work. this flywheel is in the shape of a solid uniform disk
Ksivusya [100]

 

The answer is 4.0 kg since the flywheel comes to rest the kinetic energy of the wheel in motion is spent doing the work. Using the formula KE = (1/2) I w².

Given the following:

I =  the moment of inertia about the axis passing through the center of the wheel; w = angular velocity ; for the solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.

The radius = 1.2 m and KE = 3900 J

3900 J = (1/4) m (1.2)² (52.36)²

m = 3900 J / (0.25) (1.2)² (52.36)²

m = 3.95151 ≈ 4.00 kg

6 0
3 years ago
The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What
Romashka [77]

The formula we need to use is displacement.

d=\Delta{x}=x_f-x_i, where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

2=5-x_i\Longrightarrow x_i=3.

So the initial position of truck A is 3.

Hope this helps.

r3t40

8 0
2 years ago
a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what
Andrews [41]

Answer:

  v=9.6 km/s

Explanation:

Given that

The mass of the car =  m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5  v  = 48

v=\dfrac{48}{5}\ km/s

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

3 0
2 years ago
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