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ollegr [7]
3 years ago
15

17. What are the two factors that can cause the volume of water in the ocean to change? A. Temperature and pressure B. Gravity a

nd temperature C. Pressure and salinity level D. Salinity level and temperature
Physics
1 answer:
balandron [24]3 years ago
4 0
<h2>Answer: D. Salinity level and temperature</h2>

Explanation:

The density D of the water is given by a relation between its mass m and its volume V:

D=\frac{m}{V}

Isolating the volume:

V=\frac{m}{D}

This means the <u>volume of the water will depend on its mass and its density</u>.

In this sense, the two factors that affect the volume of seawater are <u>salinity level and temperature. </u>

This is because the salinity (<u>amount of salt in water</u>) changes the its mass and its density, therefore its volume. The higher the salinity, the greater the volume.  

In the case of temperature, when it increases, the volume of water also increases and when the temperature decreases, the volume also decreases.

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Reeti has a mass of 51.0 kg. The Gravitron, a ride that spins so fast that the floor can be removed without the riders falling,
Serggg [28]

Answer:

L = 2774.4 kgm^{2}/s

Explanation:

Using the formula

L = mvr

Where L is angular momentum

m is mass

v is velocity

r is radius

m= 51kg , v=17m/s , r=3.2m

L = 51×17×3.2

L = 2774.4 kgm^{2}/s

7 0
3 years ago
Science can only test questions that involve the natural world.
Leviafan [203]

Answer:False

Explanation:

Anything with evidence it can test.

5 0
3 years ago
Read 2 more answers
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!
DaniilM [7]
The correct answer would be to express large and small numbers.
5 0
3 years ago
REMARKS The speed found in part (a) is the same as if the woman fell vertically through a distance of 21.9 m. The result of part
sasho [114]

Answer:

Yes, if the system has friction, the final result is affected by the loss of energy.

Explanation:

The result that you are showing is the conservation of mechanical energy between two points in the upper one, the energy is only potential and the lower one is only kinetic.

In the case of some type of friction, the change in energy between the same points is equal to the work of the friction forces

    W_{fr} = ΔEm

    W_{fr} = Em_{f} -Em₀

As we can see now there is another quantity and for which the final energy is lower and therefore the final speed would be less than what you found in the case without friction.

    Em_{f} =W_{fr} + Em₀

 

Remember that the work of the rubbing force is negative, let's write the work of the rubbing force explicitly, to make it clearer

    ½ m v² = -fr d + mgh

    v = √(-fr d 2/m + 2 gh)

    v = √ (2gh - 2fr d/m)

Now it is clear that there is a decrease in the final body speed.

Consequently, if the system has friction, the final result is affected by the loss of energy.

5 0
3 years ago
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