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Nadya [2.5K]
3 years ago
8

Solving systems of equations by substitution Y=6x y=5x+7

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
Y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42

dusya [7]3 years ago
6 0
First substitute 'y' in 2nd equation by right side of 1st one and you get:
Y=6x
6x=5x+7
now substract 5x from both sides of 2nd equal and you get:
6x-5x=5x+7-5x
as a result of the equal above you get:
x=7
now substitute x in very first equation by the result from above (x=7):
Y=6*7=42
x=7
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A credit card company decides to study the frequency with which its cardholders charge for items from a certain change of retail
gregori [183]

Answer:

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 25 charged purchases and a standard distribution of 2

This means that \mu = 25, \sigma = 2

Proportion above 27

1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27 - 25}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?

0.1587*100% = 15.87%

15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.

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2 years ago
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