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Nadya [2.5K]
3 years ago
8

Solving systems of equations by substitution Y=6x y=5x+7

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
Y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42

dusya [7]3 years ago
6 0
First substitute 'y' in 2nd equation by right side of 1st one and you get:
Y=6x
6x=5x+7
now substract 5x from both sides of 2nd equal and you get:
6x-5x=5x+7-5x
as a result of the equal above you get:
x=7
now substitute x in very first equation by the result from above (x=7):
Y=6*7=42
x=7
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