Answer:
Step-by-step explanation:
If m = 4, z = 9 and r = 1/6
1. 3 + m = 3 + 4 = 7
2. z - m = 9 - 4 = 5
3. 12r = 12 × 1/6 = 2
4. 60r - 4 = 60(1/6) - 4 = 10-4 = 6
5. 4m - 2 = 4(4) - 2 = 16-2 = 14
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
17>n because 17 is more than n
Answer:
£7.50
Step-by-step explanation:
Hope this helps! If I could have brainliest I'm trying to rank up :)