Answer:
the rate at which the distance between the planes is changing is 825 each hour
Step-by-step explanation:
The computation of the rate at which the distance between the planes is changing is shown below
= Travelling one plane + travelling another plane
= 450 mph + 375 mph
= 825 mi each hour
Therefore the rate at which the distance between the planes is changing is 825 each hour
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
The answer would be C
Step-by-step explanation:
You were going in the right direction but the problem was that you needed to subtract and not add. The formula should be y-y1 / x-x1 iirc. Hope this helped.
Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3
an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7
a4 = a3 + 3
a4 = 7 + 3
a4 = 10
a5 = a4+ 3
a5 = 10 + 3
a5 = 13
I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.
So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
Answer:
y = 24
Step-by-step explanation:
3x + y = 6
Solve for y
Subtract 3x from each side
3x -3x+ y = 6-3x
y = 6-3x
Let x = -6
y = 6 -3(-6)
=6+18
=24
