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Sphinxa [80]
2 years ago
12

Two planes are heading toward each other. One plane is traveling at 450 mph, and the other plane is traveling at 375 mph. What i

s the rate at which the distance between the planes is changing
Mathematics
1 answer:
gavmur [86]2 years ago
3 0

Answer:

the rate at which the distance between the planes is changing is 825 each hour

Step-by-step explanation:

The computation of the rate at which the distance between the planes is changing is shown below

= Travelling one plane + travelling another plane

= 450 mph + 375 mph

= 825 mi each hour

Therefore the rate at which the distance between the planes is changing is 825  each hour

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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Diano4ka-milaya [45]
180/3 = 60
Therefore the car traveled 60km per hour. 
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3 years ago
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Jacoby followed a recipe that requires 2 cup for water four every 3 cups of flours. if he used 8 cups flours, how many cups of w
zmey [24]

Answer:

5 and 1/3 cups of water.

Step-by-step explanation:

Set up a proportion like this:

  2:3 for the original recipe

Then a second proportion for the recipe Jacoby used:  

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Set up an equation so that the proportions equal each other. It helps if you write them in fraction form:

  \frac{2}{3} =\frac{w}{8}

Use cross multiplication to get the new equation:

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Then, divide both sides by 3 to get the amount for w, or water, by itself:

5 and 1/3 = w

I hope this helps! ☺

8 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
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\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

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3 years ago
What is the solution or solutions to 5x-y=-6 and   -2x+y=3?
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I would reccomend the app photo math its really easy to use and it answers questions like this. 
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Answer:

c

Step-by-step explanation:

this helps

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