All categories

3 years ago

10q - 20 is equivalent to _____

Mathematics

2 answers:

kkurt [141]3 years ago

7 0

The answer to your question is 10(q - 2)

NISA [10]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Select all the real numbers that are less than 70%.

andrezito [222]

Answer:

0.08, 8.2%, 0.023

Step-by-step explanation:

0.08=8%<70%

8.2%<70%

0.023=2.3%<70%

3 0

3 years ago

Give an example of a chance experiment with four possible outcomes. (Select all that apply.) A. rolling a standard die B. pickin

madreJ [45]

Answer:

A. rolling a standard die B. picking one of four unique cards C. a random number generator is used to select a whole number between 1 and 4 inclusive D. flipping two coins E. drawing a card from a deck

All are examples of a chance experiment with four possible outcomes.

Step-by-step explanation:

8 0

3 years ago

Obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is,

ki77a [65]

Answer:

C. Mean

Step-by-step explanation:

We have been given that obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is, there shouldn't be any extreme outliers).

We know that median is best measure of central tendency with extreme outliers, while mean is the best measure of central tendency when the data is normally distributed.

Mode is used when data are measured in a nominal scale.

Since the measure of intelligence from a group of college students yield a somewhat normal distribution, therefore, mean will be the best measure of central tendency.

7 0

3 years ago

Solve the following using Substitution method 2x – 5y = -13 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago

-10.23 _______ -2.3. How to solve?

nydimaria [60]

First you would turn it into long division then you would just divide from there it is pretty easy

4 0

3 years ago