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3 years ago

Who would have first made this statement while observing cork under a microscope? "The cork looks like little rooms, or cells.”

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

7 0

Answer:

A.Hooke

"The cork looks like little rooms, or cells.” A. Hooke.

Explanation:

seropon [69]3 years ago

7 0

Answer:

B. Schleiden

Explanation:

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Analyse the temperature versus time graph of water, given below.

BlackZzzverrR [31]

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

3 0

3 years ago

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)

Paha777 [63]

<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
Multiply/Divide: $\displaystyle 16.6685 \ g \ H_2O$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

6 0

3 years ago

What is the concentration of nitrate ions in a 0.225 msr(no3)2 solution?

12345 [234]

Answer : The concentration of nitrate ions is 0.450 m.

Solution : Given,

Molarity of $Sr(NO_3)_2$ = 0.225 m

The balanced ionic equation is,

$Sr(NO_3)_2\rightarrow Sr^{+2}+2NO^-_3$

From the reaction, we conclude that the 1 mole of $Sr(NO_3)_2$ produces 2 moles of $NO^-_3$ ions. That means the concentration of nitrate ions is twice the value of $Sr(NO_3)_2$ .