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Stells [14]
3 years ago
7

Analyse the temperature versus time graph of water, given below.

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

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when a volume of a gas is changed from __ L to 4.50 L, the temperature will change from 38.1 C to 15.0C
kow [346]
Assuming that the change of volumen was done at constant pressure and the quantity of gas did not change, you use Charles' Law of gases, which is valid for ideal gases:

V / T = constant => V1 / T1 = V2 / T2 => V1 = [V2 / T2] * T1.

Now plug in the numbers ,where T1 and T2 have to be in absolute scale.

T1 = 38.1 + 273.15 K = 311.25K

T2 = 15.0 + 273.15 K = 288.15K

V1 = 4.5L * 311.25K / 288.15 K = 4.86L.

Answer: 4.86
3 0
3 years ago
If I add 375 of water to 125 mL of a 0.90 M NaOH solution, what will the molarity of the diluted solution be?
madam [21]

Answer:

0.225M

Explanation:

Step 1:

Data obtained from the question. This includes:

Volume of the stock solution (V1) = 125mL

Molarity of the stock solution (M1) = 0.90 M

Volume of the diluted solution (V2) = 125 + 375 = 500mL

Molarity of the diluted solution (M2) =..?

Step 2:

Determination of the molarity of the diluted solution.

This is obtained by using the dilution formula as follow:

M1V1 = M2V2

0.9 x 125 = M2 x 500

Divide both side by 500

M2 = (0.9 x 125) /500

M2 = 0.225M

Therefore, the molarity of the diluted solution is 0.225M

6 0
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Select the correct answer. Which scientist performed the cathode ray experiment leading to the discovery of electrons? A. Dalton
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Hi,
The answer should be letter E, Thomson.
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Please help it’s a test due in five minutes! I’ll give 10 points
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weqwewe [10]
You can have as many controls as necessary, But they must remain equal at all times in order to get the most accurate results
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