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Stells [14]
3 years ago
7

Analyse the temperature versus time graph of water, given below.

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

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6 NaOH + 2 Al --> 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?
tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of Na_3AlO_3.

So, 1 mole of Al produce 1 mole of  Na_3AlO_3.     .....statement 1)

Number of moles of Al in 258 gram of Al.

n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles

Therefore, from statement 1) number of moles of Na_3AlO_3 produced is also 9.556 moles.

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Answer:

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A temperature change in a reaction indicates
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4 years ago
A chemist adds of a potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate t
Viefleur [7K]

Answer:

3.41 g

Explanation:

<em>A chemist adds 260.0 mL of a 0.0832 M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask.</em>

Step 1: Given data

  • Volume of the solution (V): 260.0 mL (0.2600 L)
  • Molar concentration of the solution (C): 0.0832 M (0.0832 mol/L)

Step 2: Calculate the moles (n) of potassium permanganate added

We will use the following expression.

n = C × V

n = 0.0832 mol/L × 0.2600 L = 0.0216 mol

Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate

The molar mass of potassium permanganate is 158.03 g/mol.

0.0216 mol × 158.03 g/mol = 3.41 g

7 0
3 years ago
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