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2 years ago

(16.5+1.5n)°(12+2n)°

Mathematics

1 answer:

tiny-mole [99]2 years ago

4 0

Answer:

1.7n +28.5

Step-by-step explanation:

you compare like terms first

1.5n add it to 2n

it will equal to 1.7

then add 16.5 to 12

it will equal to 28.5

Your new equation will be

1.7n+ 28.5 if it was equal to something let's say it was equal to 180 as an example:

your equation will be

1.7n + 28.5= 180

-28.5= -28.5

1.7n= 151.5 you would divide it

it would equal 89.1 and change.

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Convert 32 kilometers per hour to miles per day. (3.28 feet 1 meter)

bonufazy [111]

Answer:

477.09 mi/da

Step-by-step explanation:

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3 years ago

Screenshot of the question

tamaranim1 [39]

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Answer:

x = 1, x = 7

Step-by-step explanation:

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2 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

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$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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3 years ago

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2 years ago

Read 2 more answers