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Fed [463]
3 years ago
10

Is there a policy on Bainly about using notes from previous class sessions with definitions gained from googling them at the tim

e? I looked at the terms of agreement, but I didn't see anything against it. Please help.
Here's the section I've been looking at for the past 10 minutes:
"You understand that certain functions of this Brainly Services may only be available to Registered Users. Registered Users have the right to use the products, services and functionality provided by Brainly and the content and information published on the Brainly Services only within their own needs, for non-commercial purposes. Should the products, services, functionality, content or information be a subject to copyrights or any other intellectual property rights, the Registered User may use it within the allowed use under any applicable third-party licenses and subject to such copyrights and related rights. Except as otherwise provided in these Terms with regard to Brainly Subscriptions, using the products, services, functionality, content or information in accordance with these terms is free of charge"
Computers and Technology
1 answer:
Sergio039 [100]3 years ago
7 0

no there is not at least not in this section                                                              

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[1] Our son has started playing organized T-ball, a beginner’s version of baseball. [2] “Organized” is what parents call it, any
k0ka [10]
I think it is 3 no? Maybe I dunno but I am confident
6 0
3 years ago
Read 2 more answers
Software that displays advertising material when online.
liubo4ka [24]

Answer:

adware

Explanation:

Adware is a software that shows ads etc online, but also sometimes on the desktop.

Advertisware is not a real term, this is to throw you off.

Sellware is a website not a type of software

8 0
3 years ago
Read 2 more answers
You are given an array of integers, each with an unknown number of digits. You are also told the total number of digits of all t
Vlad [161]

Answer:

Explanation:

Since all of the items in the array would be integers sorting them would not be a problem regardless of the difference in integers. O(n) time would be impossible unless the array is already sorted, otherwise, the best runtime we can hope for would be such a method like the one below with a runtime of O(n^2)

static void sortingMethod(int arr[], int n)  

   {  

       int x, y, temp;  

       boolean swapped;  

       for (x = 0; x < n - 1; x++)  

       {  

           swapped = false;  

           for (y = 0; y < n - x - 1; y++)  

           {  

               if (arr[y] > arr[y + 1])  

               {  

                   temp = arr[y];  

                   arr[y] = arr[y + 1];  

                   arr[y + 1] = temp;  

                   swapped = true;  

               }  

           }  

           if (swapped == false)  

               break;  

       }  

   }

8 0
2 years ago
(Game Design) Which of the following is NOT a name of a popular digital sculpting application?
Savatey [412]

Claymation option A

Because Claymation is not the game design application.it is also called clay animation.

7 0
3 years ago
Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of
Alex73 [517]

Answer:

Explanation:

The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"

import java.util.Random;

class Brainly {

   public static void main(String[] args) {

       UseRandom useRandom = new UseRandom();

       boolean youWin = false;

       for (int x = 0; x<10; x++) {

           int num1 = useRandom.getRandom(6);

           int num2 = useRandom.getRandom(6);

           if ((num1 + num2) == 10) {

               System.out.println("Number 1: " + num1);

               System.out.println("Number 2: " + num2);

               System.out.println("You Win");

               youWin = true;

               break;

           }

       }

       if (youWin == false) {

           System.out.println("You Lose");

       }

   }

}

class UseRandom{

   public int getRandom(int n)

   {

       Random r=new Random();

       int rand=r.nextInt(n);

       return rand;

   }}

8 0
3 years ago
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