Answer:
Week=25 Hours
Weekend= 5 Hours
Step-by-step explanation:
So we need to use the info they gave us and create two equations. Firstly we know how much he gets paid per hour during the week (x) and how much he gets paid on the weekend (y).
$20x+$30y=$650
We get this because we know the combined rates he is paid times the hours should add up to the amount he earned.
The next equation will be made off of the information that he worked 5 times as many hours during the week as on the weekend. This tells us that we will take the weekend hours (y) and multiply them by 5 in order to get the week hours (x).
x=5y Now, since we have one variable by itself, we can plug it in for x in the first equation.
20(5y)+30y=650 Our first step here is to distribute the 20 to the 5y in order to eliminate the parenthesis.
100y+30y=650 Next add the like terms together (100y+30y).
Now all we have to do to find y is divide by 130 on both sides to get y alone.
130y=650
________
130 130
y=5 Now to solve for x we just plug our y value into one of the equations above. I'm going to use the second equation.
x=5(5)
x=25
Simple. Mass has to do with weight, so if mass decreases then so will the weight
Answer: Which statement is False
Step-by-step explanation:
proportional relationships
y ∝ x
=> y = kx
Comparing with line line of equation
y = mx + c
m = k , c = 0
Hence A proportional relationship must graph as a line
TRUE
at x = 0 , y = 0
Hence graph of a proportional relationship must pass through (0, 0).
TRUE
y = kx
=> y/x = k hence
Each point (or pair) in a proportional relationship must share the same ratio.
TRUE
Each point (or pair) in a proportional relationship must share the same difference.
FALSE
A9=A1+(n-1)
-2.75+(8*0.25)
-2.75+2=-0.75
Answer:

Step-by-step explanation:
We are given that

f(0)=-3,f(1)=2,f(3)=5 and f(4)=0
We have to find the polynomial
Substitute the value x=0 then ,we get
f(0)=d=-3
Substitute x=1 then we get


(equation I)
Substitute x=3 then we get


(Equation II)
Substitute x=4 then we get

(Equation III)
Equation I multiply by 3 then subtract from equation II
(Equation IV)
Equation II multiply by 4 and equation III multiply by 3 and subtract equation II from III
(Equation V)
Equation IV multiply by 2 and then subtract from equation V



Substitute the value of a in equation IV then we get




Substitute the value of b in equation I then we get



Substitute the values then we get
