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BigorU [14]
4 years ago
11

Which of the following is a physical change?

Physics
1 answer:
Talja [164]4 years ago
5 0
I believe c is correct......
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Verify the law of moment.​
larisa86 [58]

Explanation:

TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTIING ON A BODY S ,KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE,THE SUM OF THE CLOCKWISE MOMENTS ,IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.

<h2>please mark me brainlist :)</h2>
4 0
3 years ago
Read 2 more answers
You can find people belonging to each of the three consumer groups you researched in the previous task among actors, sportsperso
Natasha_Volkova [10]

Answer:

While the popularity of athletic footwear or “sneakers” has been widely assessed within academic literature, few studies to date have examined the influence of a specific sneaker subculture called “Sneakerheads”. Moreover, the brand preferences and brand identities that may exist within the Sneakerhead subculture have not been extensively examined. To address this gap in the research, semi-structured interviews were conducted with 12 male, self-identified Sneakerheads. The main goal of the research was to explore the Sneakerhead culture, while gaining an understanding of brand preferences, practices, and group identity factors. The Social Identity Theory was employed as the theoretical framework for this research. Qualitative analysis of the interviews revealed the following three topical areas: (1) , (2) , and (3)  Findings regarding the unique culture of Sneakerheads indicate a clear sense of group identity as it relates to motivations, behaviors, and brand identity within the Sneakerhead community. Moreover, the findings of this study further define the lifestyle of a Sneakerhead and shed light on their unique behaviors and practices within the culture.

Explanation:

4 0
3 years ago
A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di
solong [7]

Answer:

Before the plank will tip cat will walk 1.652 m

Explanation:

Mass of the cat along with plank m_1=7kg

Center of mass of the plank d_1=0.850m

Mass of cat m_2=3.6kg

We have to find how far right of sawhorse B.

Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.

Balancing the the torque

m_1gd_1=m_1gd_2

7\times 9.8\times 0.850=3.6\times 9.8\times d_2

d_2=1.652m

5 0
4 years ago
On his way off to college, Russell drags his suitcase 19 m from the door of his house to the car at a constant speed with a hori
Mashcka [7]

Answer:

The work done on the suitcase is, W = 1691 J

Explanation:

Given data,

The force on the suitcase is, F  = 89 N

The distance Russell dragged the suitcase, S = 19 m

The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction

The work done on the suitcase by Russell is given by the formula

                          W = F · S

Substituting the given values,

                           W = 89 N x 19 m

                           W = 1691 J

Hence, the work done on the suitcase is, W = 1691 J

8 0
4 years ago
A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows
Alona [7]

Answer:

1) The girl's acceleration at time 't' is, a=0.47 m/s²

2) The girl's acceleration at time 't₁' is, a_{1}=0 m/s²

3) The girl's acceleration at time 't₂' is,  a_{2}=-0.14 m/s²

Explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'

                                a=\frac{v-u}{t}

                                a=\frac{1.4-0}{3}

                               a=0.47 m/s²

2) The girl's acceleration at time 't₁'

                                a_{1} =\frac{v_{1} -v}{t_{1}}

                                a_{1}=\frac{1.4-1.4}{6}

                               a_{1}=0 m/s²

3) The girl's acceleration at time 't₂'

                                a_{2} =\frac{v_{2} -v_{1}}{t_{2}}

                                a_{2}=\frac{0-1.4}{10}

                               a_{2}=-0.14 m/s²

4 0
3 years ago
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