Answer:
0.0984
Explanation:
From the first diagram attached below; a free flow diagram shows the interpretation of this question which will be used to solve this question.
From the diagram, the horizontal component of the force is:
Replacing 42° for θ and 87.0° for
On the other hand, the vertical component is ;
Replacing 42° for θ and 87.0° for
However, resolving the vector, let A be the be the component of the mutually perpendicular directions.
The magnitude of the two components is shown in the second attached diagram below and is now be written as A cos θ and A sin θ
The expression for the frictional force is expressed as follows:
Where;
is said to be the coefficient of the friction
N = the normal force
Similarly the normal reaction (N) = mg - F sin θ
Replacing . The normal reaction can now be:
By balancing the forces, the horizontal component of the force equals to frictional force.
The horizontal component of the force is given as follows:
Making the subject of the formular in the above equation; we have the following:
Replacing the following values: i.e
m = 73 Kh
g = 9.8 m/s²
Then:
Thus, the coefficient of friction is = 0.0984
