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Anna35 [415]
3 years ago
15

Doug is doing work. Without knowing exactly what he is doing, which can be said about the work he is doing?

Physics
2 answers:
WARRIOR [948]3 years ago
8 0
<h3>Answer;</h3>

<em>Energy is transferred.</em>

<h3>Explanation;</h3>
  • Work is the force applied over a given distance, in other words work is the product of force and distance. That is; Work = force × distance.
  • Work is measured in Joules.
  • Energy on the other hand, is the ability to do work.
  • According to the principle of work-energy a change in the kinetic energy is equivalent to the net work don e by the object. Therefore, when work is being done energy is being transferred from one point to another.


NeX [460]3 years ago
6 0

A) Energy is transferred

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gayaneshka [121]

Answer:

2.7s

Explanation:

The solution of time required is shown below:-

In the RC circuit condenser charge 63 percent of the full charge from initial time to constant time

Now, the

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Therefore, the time required to maintain will be Equal to time (t) constant that is 2.7s

So, the correct answer is 2.7s

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3 years ago
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The formula for work is

F*d

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3 years ago
The flywheel of an engine has moment of inertia 2.50 kg m2 about its rotation axis. What constant torque is required to bring it
MrRissso [65]

Answer:

Explanation:

From the question we are told that

   The moment of inertia is  I = 2.50 \ kg \cdot m^2

    The final  angular speed is w_f =  400 rev/min  =  \frac{400 * 2\pi}{60}  = 41.89 \ rad/s

     The time taken is  t =  8.0 s

      The initial angular speed is  w_i  =  0\ rad/s

Generally the average angular acceleration is mathematically represented as

        \alpha  =  \frac{w_f - w_i }{t}

=>     \alpha  =  \frac{41.89}{8}

=>      \alpha  = 5.24 \ rad/s^2

Generally the torque is mathematically represented as

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3 years ago
You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?
Snezhnost [94]
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3 years ago
A rock thrown straight up takes 4.2 s to reach its maximum height what was its initial velocity
liubo4ka [24]

Consider the upward direction of motion as positive and downward direction of motion as negative.

a = acceleration due to gravity in downward direction = - 9.8 \frac{m }{s^{2}}

v₀ = initial velocity of rock in upward direction = ?

v = final velocity of rock at the highest point = 0 \frac{m }{s}

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Using the kinematics equation

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inserting the values

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v₀ = 41.2 \frac{m }{s}


8 0
3 years ago
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