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sergeinik [125]
3 years ago
8

The DHCP server is configured with the address lease duration set at 5 days. An employee returns to the office after an absence

of one week. When the employee boots the workstation, it sends a message to obtain an IP address. Which Layer 2 and Layer 3 destination addresses will the message contain
Computers and Technology
2 answers:
Wewaii [24]3 years ago
3 0

Answer:

both MAC and IPv4 addresses of the DHCP server

FF-FF-FF-FF-FF-FF and IPv4 address of the DHCP server

FF-FF-FF-FF-FF-FF and 255.255.255.255

MAC address of the DHCP server and 255.255.255.255

Explanation:

When the lease of a dynamically assigned IPv4 address has expired, a workstation will send a DHCPDISCOVER message to start the process of obtaining a valid IP address. Because the workstation does not know the addresses of DHCP servers, it sends the message via broadcast, with destination addresses of FF-FF-FF-FF-FF-FF and 255.255.255.255.

givi [52]3 years ago
3 0

Answer:

FF-FF-FF-FF-FF-FF and 255.255.255.255

Explanation:

At the expiration of the assigned IPV4 address, the work station will send a DHCPDISCOVER message so as to initiate the process of getting an authentic IP address. This is because the workstation cannot identify the DHCP serves address.

The second layer address broadcast FF-FF-FF-FF-FF-FF is adopted on the ethernet frame and is assumed to be broadcasted on all equipment.

255.255.255.255 is the 3rd layer address used to label the exact same host.

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Create a single list that contains the following collection of data in the order provided:
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Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

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#list that stores employee names

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#list that stores wages per hour employee

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#list that stores salary employee

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#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

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for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

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Answer:

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Explanation:

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8 bits is equal to 1 byte, therefore 64 bit is equal to (64/8 = 8) byte.

Data transferred per bus cycle = 64-bit = 8 bytes.

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The maximum Data transfer is 320 Mb/s

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